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Arte-miy333 [17]
3 years ago
7

Alison's dog is 6 pounds more than five times the weight of gales dog what algebraic equation could you make to find G which is

the way to gail's dog.
Mathematics
1 answer:
MrRissso [65]3 years ago
3 0

Answer:

g = (x - 6) / 5

Step-by-step explanation:

Given:

Let :

Alison's dog = x

Gale's dog = g

x is 6 pounds more than 5 times g

Mathematically,

x = 5g + 6

We can solve for g ;

x - 6 = 5g

Divide both sides by 5

(x - 6) / 5 = g

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the sum of the first 6 terms of a geometric series is 15624 and the common ratio is 5. what is the first term of the series?
9966 [12]

Answer:

first term a=4

Step-by-step explanation:

Sum of the first 6 terms S6 = 15624

common ratio r= 5

n= 6

first term a=?

Formula: S6= a(r^n-1)/r-1

15624 = a( 5^6-1)/5-1

15624 = a(15625-1)/4

15624= a( 15624)÷4

15624= 15624a÷4

Cross multiply

15624×4 = 15624a

62496 = 15624a

divide both sides by 15624

62496÷15624 = 15624a÷15624

4 = a

a= 4

7 0
3 years ago
PLEASE HELP ON TIMER!!!!!
Lesechka [4]

Answer:

8

Step-by-step explanation:

6 0
3 years ago
Pls help to get the answer
soldier1979 [14.2K]
When they say quotient, they want a fraction, so the answer for that would be
\frac{6}{10}
and the decimal form of that would be 0.6. You can get that from dividing 6 by 10 and solving with long division.
3 0
4 years ago
A scale drawing of a field is shown below. The drawing uses a scale of 1 in. = 14 ft. What is the area of the actual field?
svp [43]

Answer:

D. 4,704 ft²

Step-by-step explanation:

Giving a scale of 1 in. = 14 ft, to find the actual area of the field represented by the triangular drawing above, convert the length of the base and height to the actual lengths of the field using the scale.

Height of drawing = 8 in.

Actual height = 8*14 = 112 ft

Base of drawing = 6 in.

Actual base = 6*14 = 84 ft

Area of the field = area of ∆

Area = ½*base*height

Area = ½*84*112

Area = 4,704 ft²

3 0
3 years ago
1. What are the intercepts of the equation 2x+3/2y+3z=6
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3 years ago
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