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If 3x² – 2x + 7 = 0, then (x – 1/3)²
Let's work on 3x² – 2x + 7 0
1st divide all element by 3===> x² – 2/3x + 7/3
Let's complete the square of x² – 2/3x + 7/3 = (x² – 2/3x) + 7/3
We will complete the square of the parenthesis (x² – 2/3x) + 7/3
-2/3 x = -2x(time)??. so ??=1/3 & its square = 1/9
(x² – 2/3x) + 7/3 be comes [(x² - 2/3x + 1/9) - 1/9 + 7] = (x-1/3)²- 1/9 +7
(x-1/3)²- 1/9 +7 = (x-1/3)² -1/9 +63/9==>(x-1/3)² + 62/9 or
==>(x-1/3)² + 6.987654321 ===>(x-1/3)² + (≈) 7
Answer:
In front of K would be 4, leave O2 blank, and 2 would be in front of K2O.
This chemical is known as Potassium Oxide.
<u>4 K + O2 = 2 K2O</u>
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