If f(x) = - 3X -4, g(x) = 4x2 - 7x - 4, and h(x) =

A car moving at a constant speed travels 88 feet in 2 seconds. Use a proportion to find how many feet it travels in one minute

Yuki888 [10]

88 feet in 2 seconds
how many feet in 1 minute?
1 minute is 60 seconds

so, we can write a proportion and solve
feet/ seconds = feet/seconds
88/2 = x / 60
cross multiply
(88 * 60 ) = 2 * x
5280 = 2x
divide both sides by 2
2640 = x

To check:
88/2 =?= 2640 / 60
44 = 44

So the car travels 2640 feet in 60 seconds, or 1 minute.

(btw just in case you wanted to know also, 2640 feet is equal to 0.5 of a mile, that car travels 0.5 miles in 1 minute)

Hope this helps

3 0

3 years ago

HELP PLEASE

posledela

THE ANSWER IS C

step by step explanation

6 0

3 years ago

It took Max 3.5 hours to cover a certain route walking at a rate of 2.4 mph. How long would it take Max to cover the same route

Korvikt [17]

It takes 2.8 hours for Max to cover the same route by walking with 3 mph. The certain route has 8.4 miles distance which can be acquired by multiplying the velocity and the amount of time (3.5 x 2.4). Then the new amount of time can be acquired by dividing the certain route distance by the new velocity (8.4 / 3). All of the calculations above are calculated with the basic formula of constant velocity which is velocity = change of position/change of time.

7 0

4 years ago

Read 2 more answers

The functions q and r are defined as follows

kolezko [41]

Answer:

98

Step-by-step explanation:

So we have the two functions:

$g(x)=-2x-2\text{ and } r(x)=x^2-2$

And we want to find the value of r(g(4)).

To do so, first find the value of g(4):

$g(x)=-2x-2\\g(4)=-2(4)-2\\$

Multiply:

$g(4)=(-8)-2$

Subtract:

$g(4)=-10$

Now, substitute this into r(g(4)):

$r(g(4))\\=r(-10)$

And substitute this value into r(x):

$r(-10)=(-10)^2-2$

Square:

$r(-10)=100-2$

Subtract:

$r(-10)=98$

Therefore:

$r(-10)=r(g(4))=98$

3 0

3 years ago

Ill give brainliest please help with this algebra!!

creativ13 [48]

Answer:

Each of these equations solves as 1, because each one of them is an instance of the same expression being divided by itself.

This will <em>always</em> give you a value of 1, as long as the denominator does not end up with a zero value.

Take for instance the third question:

$\frac{p^4}{p^4}\\= p^4 \times p^{-4}\\= p^{(4 - 4)}\\= p^0\\= 1$

This stands true with all three questions.

HOWEVER

I say this assuming that the 5 following the first brackets in the first question is meant to be an exponent, and not a multiple. Given that the norm is to make any numeric multiples precede the brackets, I assume it is an exponent. and we're good.

It's not using superscript though, which could mean that they want it multiplied by five instead of raised to the power of.

If that's case, we can solve it the same way we solved question 20. If the bases are the same, then when multiplying or dividing the terms, you can simply add or subtract the exponents respectively:

$\frac{(4x + 2y)\times5}{(4x + 2y)^5}\\= 5(4x + 2y) \times (4x + 2y)^{-5}\\= 5(4x + 2y)^1 \times (4x + 2y)^{-5}\\= 5(4x + 2y)^{1 - 5}\\= 5(4x + 2y)^{-4}\\= \frac{5}{(4x + 2y)^{4}}$

Again, this is probably not the correct answer for question 18, as that 5 is almost guaranteed to be meant as an exponent. If it is instead a coefficient though, then this would be the answer to it.

8 0

3 years ago

Read 2 more answers

If f(x) = - 3X -4, g(x) = 4x2 - 7x - 4, and h(x) = - 5x +4, find g(-1).