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expeople1 [14]
3 years ago
8

In this triangle, cosA/cosB is equal to what? (the triangle is below)

Mathematics
1 answer:
Tpy6a [65]3 years ago
8 0

Answer:

CosA/CosB =1

CosA = Adjacent side/Hypotenuse

=AC/AB = 3/4.24

Cos B =  Adjacent side/Hypotenuse  

= BC/AB = 3/4.24

CosA/CosB = (3/4.24)/(3/4.24) = 1

The value of CosA/CosB = 1

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