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alex41 [277]
3 years ago
15

Approximate the value of V61 to the nearest hundredth. No links please!

Mathematics
1 answer:
Nookie1986 [14]3 years ago
6 0
The answer above is scam. They just tyr to get potns. The correct andwr dos 3736.
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What is 30% of x+(x-10)​
anygoal [31]

Answer:

(3x - 15)/5

Step-by-step explanation:

To find 30% of x+(x-10) we divide x+(x-10) by 100 then multiply it by 30

(x+(x-10)) ÷ 100 × 30 = (3x - 15)/5

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3 years ago
Select all that apply.
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10:4 15:6 20:6 if those aren’t on there I ain’t ur guy
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3 years ago
Find the value of r<br> 13<br> 15<br> 18<br> 28
Murljashka [212]

Answer:

it's supposed to be 26/25.6

4 0
4 years ago
Which of the following could be points on the unit circle?
ipn [44]

Answer:

Points A and C are on the unit circle

Step-by-step explanation:

The unit circle is a circle of radius 1, that is, all the points that are inside the circle have the sum of the squares of its coordinates that are at most 1. Here, we have to test this for each option.

In options B and D, the coordinates 13/7 and 4/3, respectively, means that this sum will be larger than 1, and this points will not be on the unit circle. Now we text for options A and C.

A. ( 5/13, 12/13)

\sqrt{(\frac{5}{13})^2+(\frac{12}{13})^2} = \sqrt{\frac{25}{169}}+\sqrt{\frac{144}{169}} = \sqrt{\frac{169}{169}} = \sqrt{1} = 1

Since the sum of the squares is 1, the point is on the unit circle.

C. (1/3, 2/3)

\sqrt{(\frac{1}{3})^2+(\frac{2}{3})^2} = \sqrt{\frac{1}{9}}+\sqrt{\frac{4}{9}} = \sqrt{\frac{5}{9}}

Since the sum of the squares is less than 1, the point is on the unit circle.

5 0
3 years ago
Hurry help me solve this equation.
Rainbow [258]

Answer:

Step-by-step explanation:

the 3rd one

3 0
3 years ago
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