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Anika [276]
3 years ago
9

.) Which expression is equivalent to 15c+20? 15(c+20) 15(c +4) 5(3C+4 5(3c+20)

Mathematics
2 answers:
Alla [95]3 years ago
7 0

Answer:

5(3c+4)

<em>5×3c= 15c</em>

<em>5×3c= 15c5×4=20</em>

<em>5×3c= 15c</em>

<em>5×4=20</em>

<em>=15c+20</em>

kap26 [50]3 years ago
5 0

Answer:

5(3c + 4) is equivalent

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Simplify \frac{1}{2}\imath n(x+3)​2​​1​​ın(x+3) to \frac{\imath n(x+3)}{2}​2​​ın(x+3)​​

\frac{\imath n(x+3)}{2}-\imath nx=0​2​​ın(x+3)​​−ınx=0


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Add \imath nxınx to both sides

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Multiply both sides by 22

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Cancel \imathı on both sides

n(x+3)=nx\times 2n(x+3)=nx×2


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Divide both sides by nn

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Subtract 33 from both sides

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6 0
4 years ago
A rectangular swimming pool is 8 ft deep. One side of the pool is 4.5 times longer than the other. The amount of water needed to
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Step-by-step explenation:

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3 years ago
The owner of a local golf course wants to estimate the difference between the scores of golfers on his golf course and the score
Olenka [21]

Answer:

(8) The correct option is (3).

(2) The correct option is (1).

Step-by-step explanation:

(8)

The hypothesis can be defined as:

<em>H₀</em>: There is no difference between the two population means, i.e. <em>μ₁ </em>= <em>μ₂</em>.

<em>Hₐ</em>: There is a difference between the two population means, i.e. <em>μ₁ </em>≠ <em>μ₂</em>.

The decision rule of the test based on confidence interval is:

If the (1 - <em>α</em>) % confidence interval consists the null hypothesis value then the null hypothesis is not rejected. and vice-versa.

The 90% confidence interval for the paired difference between means is, (-3.31, 14.74).

The interval consists the null value, 0.

Thus, the null hypothesis was failed to be rejected.

<u>Conclusion:</u>

No significant difference exists between the average difference in scores and the differences were calculated as 0.

Thus, the correct option is (3).

(2)

A (1 - <em>α</em>) % confidence interval implies that there is (1 - <em>α</em>) % chance of the population parameter to be contained in this interval.

Or if 100 such intervals are constructed then (1 - <em>α</em>) of these intervals will consist the true parameter value.

The 99% confidence interval for the difference between means is, (-0.124, 13.85).

This interval implies that the true mean difference between the two populations lies in this interval with probability 0.99.

<u>Conclusion:</u>

We are 99% confident that the difference between the average age of all men and all women who play golf at the course is between -0.124 and 13.85.

Thus, the correct option is (1).

4 0
3 years ago
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