Figure A: 5•3=15
Figure B: 3•6=18
Figure C: 4•4=16
Figure D: 4•3=12
Figure B has the largest perimeter
From the figure the given line passes through the points (0, 0) and (-4, 8).
Recall that the equation of a straight line is given by

Thus, The equation of the given figure is given by
Answer:
m=28
n=21
Step-by-step explanation:
3×4=12
7×4=28
28×1.75=49
12×1.75=21
Using the law of cosine for Triangle KJL, we can write:

Using the values of k,j and l, we can write:

Rounding to nearest integer, the measure of angle J will be 48 degrees.
So option B gives the correct answer