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2 years ago

5

If you were given the choice of between more initial zombies, but a slower growth rate or fewer initial zombies, but a greater g

rowth rate, which would you pick and why?

2 answers:

Digiron [165]2 years ago

5 0

I would choose to have a higher initial rate of zombies with a slower growth rate because (although it would be difficult in the beginning) i would have more time to prepare for the zombies.

natulia [17]2 years ago

4 0

Answer:

I would chose more initial zombies, but a slower growth rate because if their growth rate is slow then you have time to find weapons and build you a shelter then as they grow stronger you grow stronger so you have a better chance of surviving

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What is 1 + 1 i need help.

Anastasy [175]

Answer:

2

Step-by-step explanation:

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2 years ago

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Describe the transformation from y= x + 4 to y= .5x + 4 Group of answer choices compresses stretches shifts right 4 shifts left

Nina [5.8K]

Answer:

This type of transformation is a horizontal stretch.

<em></em>

Step-by-step explanation:

Given

$y = x + 4$

$y = .5x + 4$

Required

Determine the type of transformation

The first function can be expressed as:

$f(x) = x + 4$

While the second function is:

$g(x) = f(0.5x)$

Solving f(0.5x), we have to substitute 0.5x for x in $f(x) = x + 4$

$f(0.5x) = 0.5x + 4$

So:

The second function is:

$g(x) = 0.5x + 4$

<em>This type of transformation is a horizontal stretch.</em>

<em></em>

<em>i.e. f(x) stretched to g(x)</em>

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3 years ago

Which expression is equivalent to (4p^-4 q)^-2/ 10pq^-3?

Anit [1.1K]

Answer:

$\dfrac{p^{7} q}{160}$

Step-by-step explanation:

$\dfrac{(4p^-4 q)^-2}{10pq^-3} =$

$= \dfrac{4^{-2}p^{-4\times (-2)} q^{-2}}{10pq^-3}$

$= \dfrac{4^{-2}}{10}p^{8-1} q^{-2-(-3)}$

$= \dfrac{1}{4^2 \times 10}p^{7} q^{-2 + 3}$

$= \dfrac{1}{160}p^{7} q$

$= \dfrac{p^{7} q}{160}$

4 0

2 years ago

Read 2 more answers

Find the period of the function y=3/2 tan(1/3^x)<br> A) π/3<br> B) π/6<br> C) 3 π<br> D) π

Anna71 [15]

C is the right answer because the period should be pi/(1/3), so the answer is 3pi

3 0

2 years ago

HELP ASAP : Find the largest value of n such that 5x^2+nx+48 can be factored as the product of two linear factors with integer c

Anna71 [15]

Answer:

$n=241$

Step-by-step explanation:

We are given

$5x^2+nx+48$

Let's assume it can be factored as

$5x^2+nx+48=(5x-s)(x-r)$

now, we can multiply right side

and then we can compare it

$5x^2+nx+48=5x^2-5rx-sx+rs$

$5x^2+nx+48=5x^2-(5r+s)x+rs$

now, we can compare coefficients

$rs=48$

$5r+s=-n$

$n=-(5r+s)$

now, we can find all possible factors of 48

and then we can assume possible prime factors of 48

$48=-+(1\times 48)$

$48=-+(2\times 24)$

$48=-+(3\times 16)$

$48=-+(4\times 12)$

$48=-+(6\times 8)$

Since, we have to find the largest value of n

So, we will get consider larger value of r because of 5r

and because n is negative of 5r+s

so, we will both n and r as negative

So, we can assume

r=-48 and s=-1

so, we get

$n=-(5\times -48-1)$

$n=241$

7 0

3 years ago