The answer you are looking for is A, I'm a little rusts at these but that should your answer have a good day!
If a secant<span> and a </span><span>tangent of a circle </span><span>are drawn from a point outside the circle, then the product of the lengths of the secant and its external segment equals the square of the length of the tangent segment.
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y</span>² = 7(15+7)
<span>y</span>² = 7*22
<span>y</span>² = 154
<span>y = </span>√154
<span>y = 12.4 </span>← to the nearest tenth<span>
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The 8th term is 33 and I don't think any of the options are there
I believe the answer is 3240^9/2 g^33/8
The sum of the exterior angles of all polygon is always equal to 360°. The exterior angle sharing the same side with that of the right angle of the triangle is equal to 90°. If the other exterior angles are 13x and 14x then, they add up to 270°.
The equation that would allow us to determine the values of the angles are,
13x + 14x = 270
x = 10
The exterior angles are 130 and 140°. The exterior angle and the interior angle always add up to 180°.
Interior angle 1: 180° - 130° = 50°
Interior angle 2: 180° - 140° = 40°
Therefore, the measures of the two acute angles of the triangle are 50° and 40°.