Answer:
asa
Step-by-step explanation:
Answer: AA similarity theorem.
Step-by-step explanation:
Given : AB ∥ DE
Prove: ΔACB ≈ ΔDCE
We are given AB ∥ DE. Because the lines are parallel and segment CB crosses both lines, we can consider segment CB a transversal of the parallel lines. Angles CED and CBA are corresponding angles of transversal CB and are therefore congruent, so ∠CED ≅ ∠CBA.
Also ∠C ≅ ∠C using the reflexive property.
Therefore by AA similarity theorem , ΔACB ≈ ΔDCE
- AA similarity theorem says that if in two triangles the two pairs of corresponding angles are congruent then the triangles are similar .
Answer:
4
Step-by-step explanation:
Let's find a pattern.
2^0=1
2^1=2
2^2=4
2^3=8
2^4=16
2^5=32
2^6=64
2^7=128
2^8=256
So starting after power of 0, the pattern begins at power=1. The pattern is 2,4,8,6 for the units digit. Since the pattern repeats in 4, then we shall divide the power in question by 4 seeking it's remainder.
Remainder=1 implies unit digit is 2 (see 2^1=2)
Remainder=2 implies unit digit is 4 (see 2^2=4)
Remainder=3 implies unit digit is 8 (see 2^3=8)
Remainder=0 implies unit digit is 6 (see 2^4=16)
2014/4 = 503 + 2/4
So remainder=2 implies unit digit is 4.
To find the answer you must know what 3x - 2y=
