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Zepler [3.9K]
3 years ago
15

For brainliest answer this ASAP

Mathematics
1 answer:
krok68 [10]3 years ago
5 0

Answer:

The hypotenuse of a right triangle is 4m longer than the shorter leg and 2m longer than the longer leg. What are the lengths of the sides?

Just for variety, consider the hypotenuse = h, the short leg h-4 and the long leg h-2.

c^2 = a^2 + b^2; so h^2 = (h-4)^2 + (h-2)^2; h^2 = h^2 - 8h + 16 +h^2 -4h +4;

h^2 -12h +20 = 0 factors to (h - 10)(h - 2) = 0 so h = 2 or h = 10

Since (h - 2) = (2 - 2) = 0 and a triangle cannot have a side of zero length, 10 is the length of the hypotenuse.

h^2 = (h-4)^2 + (h-2); 10^2 = (10-4)^2 + (10-2); (10)^2 = (6)^2 + (8)

The hypotenuse is 10 cm, short leg 6 cm and long leg 8 cm.

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Line segment JM has endpoints with coordinates -2 and 14 on a number line. Points K and L are on segment JM. K has a coordinate
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Answer:

B. \frac{25}{64}

Step-by-step explanation:

Please find the attachment.  

We have been given that line segment JM has endpoints with coordinates -2 and 14 on a number line. Points K and L are on segment JM. K has a coordinate of 2 and point L has a coordinate of 8.

The probability that the first point is positioned on JL would be \frac{10}{16} as there are total 10 points on JL as L is at point 8 and J is at point -2 so (8--2=8+2=10). Total number of points on the number line JM is (14--2=14+2=16)  

The probability that second point is not placed on KL would be:

P(\text{The point is not on KL)}=1-\text{probability that point is on KL}

P(\text{The point is not on KL)}=1-\frac{\text{Total points on KL}}{\text{Total points on JM}}

P(\text{The point is not on KL)}=1-\frac{(8-2)}{16}

P(\text{The point is not on KL)}=1-\frac{6}{16}

P(\text{The point is not on KL)}=\frac{16-6}{16}

P(\text{The point is not on KL)}=\frac{10}{16}

\text{The probability of getting 1st point on Jl and second point is not on KL}=\frac{10}{16}\times \frac{10}{16}

\text{The probability of getting 1st point on Jl and second point is not on KL}=\frac{5}{8}\times \frac{5}{8}

\text{The probability of getting 1st point on Jl and second point is not on KL}=\frac{25}{64}

Therefore, our desired probability will \frac{25}{64} and option B is the correct choice.

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