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Maurinko [17]
3 years ago
6

Use inverse operations to solve equation 15=x/6-1​

Mathematics
1 answer:
beks73 [17]3 years ago
7 0

Answer:

x=90.

Step by step explanation:

To solve the expression 15=\frac{x}{6}-1, and obtaining a value for x we can do the following:

  1. Add 1 both sides of the equation. This will result in 15+1=\frac{x}{6}-1+1⇒16=\frac{x}{6}.
  2. Multiply both sides by 6, which yields 15\times6=\frac{x}{6}\times6. This results in 90=x.

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Answer:

\large\boxed{\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\dfrac{\sqrt5}{x^2y}}

Step-by-step explanation:

\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\sqrt{\dfrac{55}{11}\cdot\dfrac{x^7}{x^{11}}\cdot\dfrac{y^6}{y^8}}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\=\sqrt{5x^{7-11}y^{6-8}}=\sqrt{5x^{-4}y^{-2}}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt5\cdot\sqrt{x^{-4}}\cdot\sqrt{y^{-2}}=\sqrt5\cdot\sqrt{x^{(-2)(2)}}\cdot\sqrt{y^{(-1)(2)}}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt5\cdot\sqrt{(x^{-2})^2}\cdot\sqrt{(y^{-1})^2}\qquad\text{use}\ \sqrt{a^2}=a

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3 years ago
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