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beks73 [17]
4 years ago
6

For my sister 20019190 plz take it

Mathematics
2 answers:
ehidna [41]4 years ago
8 0

Answer:

Step-by-step explanation:

ok

Paha777 [63]4 years ago
3 0

Answer:

i dont understand

Step-by-step explanation:

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6 1/6 6 1/3 6 2/3 6 3/2
Vladimir [108]

Given:

The expression is

\sqrt{\sqrt[3]{6}}

To find:

The simplified form of the given expression.

Solution:

We have,

\sqrt{\sqrt[3]{6}}

Using the properties of radical and exponent, we get

=(\sqrt[3]{6})^{\frac{1}{2}}                     [\because \sqrt{x}=x^{\frac{1}{2}}]

=\left(6^{\frac{1}{3}}\right)^{\frac{1}{2}}                  [\because \sqrt[n]{x}=x^{\frac{1}{n}}]

=6^{\frac{1}{3}\times\frac{1}{2}}                    [\because (a^m)^n=a^{mn}]

=6^{\frac{1}{6}}

Therefore, the correct option is A.

8 0
3 years ago
What's the nth root of 0.81
GREYUIT [131]

Answer:

Step-by-step explanation:

0.9

8 0
4 years ago
Read 2 more answers
In what ways do the agati and the Brazil nut tree depend on each other ​
nirvana33 [79]

Answer:

In the Amazon rainforest, the agouti (a small rodent) and the brazil nut tree are very dependent on each other. The brazil nut tree drops its pods when they ripen, but they would not split open if it were not for the agouti's sharp teeth - the only forest animal which can split the tough pods. The agouti benefits by eating the brazil nuts, but like squirrels, agoutis hide and bury surplus nuts - and many of these take root, thus replenishing stocks of brazil nut trees.

7 0
3 years ago
How do you translate a figure up ?
rusak2 [61]
I don’t know how to answer this problem sorry
5 0
3 years ago
Point A is located at (?5, 2) on a coordinate grid. Point A is translated 1 unit to the left and 5 units down to create point A'
svp [43]
ANSWER

C) 5.1 units

EXPLANATION

The coordinates of A are (5,2).


If this point is translated 1 unit to the left and 5 units down to create point A'.

Then A' has coordinates

A(5,2)\rightarrow \: A'(5-1,2-5)


A(5,2)\rightarrow \: A'(4, - 3)



The distance between A and A' is calculated using the distance formula,

|AA'| =  \sqrt{ {(5 - 4)}^{2}  +  {(2 -  - 3}^{2} }


|AA'| =  \sqrt{ {(1)}^{2}  +  {(5)}^{2} }


|AA'| =  \sqrt{ 26}


|AA'| =  5.099

We round to the nearest tenth to obtain,

|AA'| =5.1 \: units


The measurement that is closed to the distance is 5.1 units

4 0
4 years ago
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