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Vladimir [108]
2 years ago
6

What is the inverse of the function f(x) = 2x 1? h(x) = one-halfx – one-half h(x) = one-halfx one-half h(x) = one-halfx – 2 h(x)

= one-halfx 2
Mathematics
1 answer:
lidiya [134]2 years ago
8 0

Answer:

214

Step-by-step explanation:

24

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Three times a number less than the sum of twice the number and 1
BabaBlast [244]
That would be 3n<2n+1
4 0
3 years ago
Keely scored 128 points, which was 4 times as many points as Grayson scored. Which equation can be used to find the number of po
Ludmilka [50]

Answer:

32

Step-by-step explanation:

take 128 divide by 4

4 0
2 years ago
Ashley can ride her bicycle 15 miles in 2 hours there are 60 minutes I 1 hour and there are 1760 years in 1 mile how many yards
il63 [147K]

Answer:

speed is given by:

speed=distance/time

given that:

1 mile=1,760 yards

1 hour=60 min

then the speed in yards/sec will be:

distance Ashley covered is 15 miles

time=2 hours

thus;

speed=(15x1760)/(2x60)

=220 yards/ min

Step-by-step explanation:

Hi hope helps you :)

5 0
2 years ago
A highway department executive claims that the number of fatal accidents which occur in her state does not vary from month to mo
den301095 [7]

This question is incomplete, the complete question;

A highway department executive claims that the number of fatal accidents which occur in her state does not vary from month to month. The results of a study of 193 fatal accidents were recorded. Is there enough evidence to reject the highway department executive's claim about the distribution of fatal accidents between each month? Month Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec Fatal Accidents 11 13 22 11 15 29 15 9 13 15 22 18

Step 10 of 10 : State the conclusion of the hypothesis test at the 0.1 level of significance.

Answer: H₀ : The distribution of fatal accidents between each month is same

Step-by-step explanation:

H₀ : The distribution of fatal accidents between each month is same

H₁ : The distribution of fatal accidents between each month is different

Let the los be alpha 0.10

given data ;

       Observed    Expected  

Mon   Freq (Oi)   Freq Ei       (Oi-Ei)^2 /Ei

Jan      11    16.0833        1.606649

Feb      13    16.0833        0.591105

Mar      22    16.0833        2.176598

Apr       11    16.0833        1.606649

May     15    16.0833        0.072971

Jun     29    16.0833        10.373489

Jul     15    16.0833        0.072971

Aug       9    16.0833        3.119603

Sep      13    16.0833        0.591105

Oct      15    16.0833        0.072971

Nov      22    16.0833        2.176598

Dec      18    16.0833       0.228411

Total:   193     93                22.689119

Expected Freq ⇒ 193 / 12 = 16.08333

Test Statistic, x² : 22.6891

Num Categories: 12

Degrees of freedom: 12 - 1 = 11

Critical value X² : 24.725

P-Value: 0.0195

since Chi-square value < Chi-square critical value

and P-value > alpha 0.01 so we accept H₀

Therefore we conclude that the distribution of fatal accidents between each month is same

7 0
3 years ago
Find the value of each expression. Show your work.
luda_lava [24]

Answer:

A) 1.44

B) 25 - 3x^4

C) 3

Step-by-step explanation:

Sadly, I cannot show work, but those are the answers

7 0
2 years ago
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