Answer:
1. RQP
2. QOP
Step-by-step explanation:
the answer for the first question is RQP and the answer for the second question is QOP
Answer:
46.57
Step-by-step explanation:
Given that:
h(t) = 37t - 4.9t²
When the ball reaches the ground, then the height is zero;
So, we equate h(t) to zero and solve for t
37t - 4.9t² = 0
t = 0, 7.55
Let the Initial time be a = t = 0
The time the ball reaches the ground be b = 7.55
So, the average height can now be calculated as:
Average height =
=
=
=
= 46.57091665
≅ 46.57 to (2 decimal places)
Answer:The slope of a line measures the steepness of the line. Most of you are probably familiar with associating slope with "rise over run". Rise means how many units you move up or down from point to point. Run means how far left or right you move from point to point. On the graph, that would mean a change of x values.
Step-by-step explanation:
Answer:
x=340
y=-165
Step-by-step explanation:
x/10+y/5=1 Equation 1
x/8+y/6=15 Equation 2
Using elimination method, we multiply equation 1 by 1/6, the coefficient of y in equation 2 and then also multiply equation 2 by 1/5, the coefficient of y in equation 1, this will make you have the same coefficient and then easy to eliminate.
1/6(x/10+y/5=1)
x/60+y/30=1/6 Equation 3
1/5(x/8+y/6=15)
x/40+y/30=15/5
x/40+y/30=3 Equation 4
We subtract equation 3 from equation 4 to eliminate y
x/40-x/60= (3x-2x)/120= x/120
y/30-y/30
3-1/6= (18-1)/6= 17/6
We now have
x/120=17/6
Cross multiply
6x=2040
Divide both sides by 6
6x/6=2040/6
x=2040/6
x=340
Substitute x for 340 in equation 1
x/10+y/5=1
340/10+y/5=1
34+y/5=1
y/5=1-34
y/5=-33
Cross multiply
y=-33(5)
y=-165