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goblinko [34]
3 years ago
10

Given a quadratic function, y = ax + bx+c, what happens to the graph when "a" is positive?

Mathematics
1 answer:
guajiro [1.7K]3 years ago
8 0

Answer:

d

Step-by-step explanation:

it is opened up because the voeff of X^2 tetm is positive

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Number of emails received in one account every day from the day it was created until it was canceled:
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The answer is B. Complete information.

A sample means only part of the whole. From the day the email was created till it was cancelled is the whole population. Consider that no mails will no longer go in because it is closed so no more additional information or data will enter that category. So it would be considered as complete. If the situation were to ask from one point to another before it was cancelled it would be considered as a sample. 
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5 0
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Read 2 more answers
Given the functions f (x) = x^2 + 4 and g (x) = 3x+ 8 what is a solution for the equation ? x^2 + 4 = 3x + 8 A. 0 B. 1 C. 2 D. 4
k0ka [10]

Answer:

D

Step-by-step explanation:

Let's solve your equation step-by-step.

x2+4=3x+8

Step 1: Subtract 3x+8 from both sides.

x2+4−(3x+8)=3x+8−(3x+8)

x2−3x−4=0

Step 2: Factor left side of equation.

(x+1)(x−4)=0

Step 3: Set factors equal to 0.

x+1=0 or x−4=0

x=−1 or x=4

Answer:

x=−1 or x=4

6 0
4 years ago
Which expression is equivalent to 3(2/3p+3-1/3p-5)
kaheart [24]

Answer:

− 6

Step-by-step explanation:

4 0
3 years ago
Given that f(x) = x2 − 3x + 3 and g(x) = the quantity of x minus one, over four, solve for f(g(x)) when x = 5.
Katena32 [7]

g(x) = the quantity of x minus one, over four

g(x) = (x-1)/4

g(5) = (5-1)/4

g(5) = 4/4

g(5) = 1


f(x) = x2 − 3x + 3

f(g(5)) =1^2 − 3(1) + 3

f(g(5)) = 1 - 3 + 3

f(g(5)) = 1


7 0
4 years ago
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