Group and factor
undistribute then undistribute again
remember
ab+ac=a(b+c)
this is important
6d^4+4d^3-6d^2-4d
undistribute 2d
2d(3d^3+2d^2-3d-2)
group insides
2d[(3d^3+2d^2)+(-3d-2)]
undistribute
2d[(d^2)(3d+2)+(-1)(3d+2)]
undistribute the (3d+2) part
(2d)(d^2-1)(3d+2)
factor that difference of 2 perfect squares
(2d)(d-1)(d+1)(3d+2)
77.
group
(45z^3+20z^2)+(9z+4)
factor
(5z^2)(9z+4)+(1)(9z+4)
undistribuet (9z+4)
(5z^2+1)(9z+4)
0.8
you find how much he needed so:
24*0.3=7.2
than 8 he had , so whats left over
8-7.2=0.8
Answer:
x = 0.25
Step-by-step explanation:
When logs are added together, they are actually multiplied and then the logs taken of the product.
That sentence is actually correct, but you are going to have to read it a couple of times. You might understand it if I actually just solve the problem.
ln(2x) + ln(2) = 0 Combine the two subjects to make 1 ln.
ln (2)(2x) = 0 Now take the antilog
ln(4x) = 0
antilog ln(4x) = e^0 e^0 = 1
4x = 1 See your last problem.
x = 1/4
Now the question is "What's the answer?" It might be 1/4 but I doubt it. A better choice would be x = 1/4 or x = 0.25
I'd try the last one first.
Answer:
y - 4 = (2/3)(x - 7)
Step-by-step explanation:
(see attached for reference)
we are given slope, m = 2/3 and point (x₁, y₁) is (7,4)
y - y₁ = m(x - x₁)
substituting the given values into the general equation
y - y₁ = m(x - x₁)
y - 4 = (2/3)(x - 7)
3(-4+8) distribute the 3 to -4 and 8
(-12 + 24) add the terms
12
