Question

Use the x-intercept method to find all real solutions of the equation. x^3-6x2+3x+10=0

Answer 1

Answer:

Three solutions were found :

x = 5

x = 2

x = -1

Step-by-step explanation:

 

Answer 2

Answer:

d. $x=-1,2,\:or\:5$

Step-by-step explanation:

The given equation is;

$x^3-6x^2+3x+10=0$

To solve by the x-intercept method we need to graph the corresponding function using a graphing calculator.

The corresponding function is

$f(x)=x^3-6x^2+3x+10$

The solution to $x^3-6x^2+3x+10=0$ is where the graph touches the x-axis.

We can see from the graph  that; the x-intercepts are;

(-1,0),(2,0) and (5,0).

Therefore the real solutions are:

$x=-1,2,\:or\:5$