The answer is option B. In the distributive property you need to multiply the constant that is outside of the parenthesis, with the terms that are inside :)
Answer:
А.The system has two solutions, but only one is viable because the other results in a negative width.
Step-by-step explanation:
Given
Let:
length of play area A
width of play area A
length of play area B
width of play area B
Area of A
Area of B
From the question, we have the following:
The area of A is:
This gives:
Open bracket
The area of B is:
Substitute:
Open brackets
Expand
We have that:
This gives:
Collect like terms
Using quadratic calculator, we have:
or 
--- approximated
But the width can not be negative; So:
19) 15 <= 9 + 3x
15) x = 23,24,25
17) x <= 115
9) Second line
11) g > 20, don't fill in dot, any number greater than 20
1) -3 + h<= 3.4
3) No, x > -2
5) x > 14, don't fill in dot, any number greater than 14
7) k<=20, fill in dot, 20 or any larger number
(took me while to type this out lol cause on mobile)
The correct answer is Hector's, 4 degrees, and Gale's.
Answer:
The first one:
−8x4−14x2−3
Step-by-step explanation:
(-4•2-1)(2•2+3)
-4•2 = -8
-8 - 1 = -9
(-9)(2•2+3)
2•2 = 4
4+3 = 7
(-9)(7) = -63
Now we find the one that equals -63:
-8•4-14•2-3
(-8•4)-14•2-3
-32-14•2-3
-32-(14•2)-3
-32-28-3
(-32-28)-3
-60-3
-60-3 = -63
BAM! THE ANSWER!
