The graph of a quadratic function passes through the points (0,-4) and (-2,0). What is the zero of the function?

Suppose y varies inversely with x, and y = 25 when x = 1/5. What is the value of y when x = 5 ?

34kurt

Answer:

y = 1

Step-by-step explanation:

Given that y varies inversely with x then the equation relating them is

y = $\frac{k}{x}$ ← k is the constant of variation

To find k use the condition y = 25 when x = $\frac{1}{5}$ , then

25 = $\frac{k}{\frac{1}{5} }$ = 5k ( divide both sides by 5 )

5 = k

y = $\frac{5}{x}$ ← equation of variation

When x = 5, then

y = $\frac{5}{5}$ = 1

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%20%5Cfrac%7B3%7D%7B4%7D%20x%20%2B%20%20%5Cfrac%7B5%7D%7B6%7D%20%20%3D%205x%20-%20%20%5Cfra

jonny [76]

Answer:

nos agoi o se

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Rewrite the following quadratic functions in intercept or factored form. Show your work.

Dmitry [639]

<u>Answer: </u>

f(x) = 3(x+2)(x-2)

<u>Step-by-step explanation: </u>

We are given the following the quadratic function and we are to rewrite it in intercept or factored form:

$f(x) = 3x^2 - 12$

We can factorize the given function so taking the common factors out of it to get:

$f(x)=3x^2 - 12$

$f(x) = 3 (x^2 - 4)$

The term $(x^2-4)$ is in the form $a^2-b^2$ so it can further be factorized to give:

$f(x) = 3 (x+2)(x-2)$

Therefore, the factored form of the given quadratic function is f(x) = 3(x+2)(x-2).

7 0

2 years ago

Read 2 more answers

A surveyor leaves her base camp and drives 42km on a bearing of 032degree she then drives 28km on a bearing of 154degree,how far

ValentinkaMS [17]

Answer:

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

Step-by-step explanation:

The final position of the surveyor is represented by the following vectorial sum:

$\vec r = \vec r_{1} + \vec r_{2} + \vec r_{3}$ (1)

And this formula is expanded by definition of vectors in rectangular and polar form:

$(x,y) = r_{1}\cdot (\cos \theta_{1}, \sin \theta_{1}) + r_{2}\cdot (\cos \theta_{2}, \sin \theta_{2})$ (1b)

Where:

$x, y$ - Resulting coordinates of the final position of the surveyor with respect to origin, in kilometers.

$r_{1}, r_{2}$ - Length of each vector, in kilometers.

$\theta_{1}, \theta_{2}$ - Bearing of each vector in standard position, in sexagesimal degrees.

If we know that $r_{1} = 42\,km$ , $r_{2} = 28\,km$ , $\theta_{1} = 32^{\circ}$ and $\theta_{2} = 154^{\circ}$ , then the resulting coordinates of the final position of the surveyor is:

$(x,y) = (42\,km)\cdot (\cos 32^{\circ}, \sin 32^{\circ}) + (28\,km)\cdot (\cos 154^{\circ}, \sin 154^{\circ})$

$(x,y) = (35.618, 22.257) + (-25.166, 12.274)\,[km]$

$(x,y) = (10.452, 34.531)\,[km]$

According to this, the resulting vector is locating in the first quadrant. The bearing of the vector is determined by the following definition:

$\theta = \tan^{-1} \frac{10.452\,km}{34.531\,km}$

$\theta \approx 16.840^{\circ}$

And the distance from the camp is calculated by the Pythagorean Theorem:

$r = \sqrt{(10.452\,km)^{2}+(34.531\,km)^{2}}$

$r = 36.078\,km$

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

5 0

3 years ago

If y varies directly with x when y=8,x=20 find the value of x when y=42

Alecsey [184]

The value of x is 105 when y=42

Step-by-step explanation:

A direct proportion means that the change in one quantity will also cause the change in other quantity

Given

y varies directly with x

x ∝ y

when the proportionality symbol is removed a proportionality constant is introduced

$x=ky\\k=\frac{x}{y}\\Putting\ y=8\ and\ x=20\\k=\frac{20}{8}\\k = \frac{5}{2}\\So,\ the\ equation\ will\ be\\x=\frac{5}{2}y\\Putting\ y=42\\x=\frac{5}{2}*42\\x=5*21\\x= 105$

The value of x is 105 when y=42

Keywords: Proportion, Direct variation

Learn more about proportion at:

#LearnwithBrainly

5 0

3 years ago