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Taya2010 [7]
3 years ago
6

Perry and Jacob each improved their yards by planting hostas and ivy. They bought their supplies from the same store. Perry spen

t $122 on 7 hostas and 5 pots of ivy. Jacob spent $100 on 5 hostas and 5 pots of ivy. What is the cost of one hosta and the cost of one pot of ivy. ENTER your answer in the format hosta=## ivy=##
Mathematics
1 answer:
marissa [1.9K]3 years ago
3 0

Answer:

hosta=11 ivy=9

Step-by-step explanation:

Logically thinking... $20 for 1 h and 1 i

So I would say $11 H and $9 I

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Scientists estimate the rate of a kangaroo pouncing at full speed to be 66 feet per second. Write a function rule to describe th
aleksandrvk [35]
Distance equals rate times time, so:
D = (66 ft/s) * t
4 0
3 years ago
Let p=x^2-2 which equation is equivalent to (x^2-2)^2+18=9x^2-18 in terms of p
Bad White [126]

Answer:

The equivalent equation is p^2 + 18 = 9p

Step-by-step explanation:

p is given by the following relation:

p = x^2 - 2

And we are given the following equation:

(x^2 - 2)^2 + 18 = 9x^2 - 18

On the right side, we can simplify. So

(x^2 - 2)^2 + 18 = 9(x^2 - 2)

Replacing x^2 - 2 by p, the equation is:

p^2 + 18 = 9p

6 0
3 years ago
Shen needs 271 programs for the school play on Thursday. How many boxes of programs will he need, given that each box contains 3
lesantik [10]
7 because if you divide it by 35, it's seven.
8 0
3 years ago
In the figure below, F is between E and G, and G is between F and H. IF EH=9, FH = 7, and EG=6, find FG.
shutvik [7]

Answer:

EH = 9

FH = 7

EG = 6

EF = EH - FH

EF = 9 -7

EF = 2

FG = EG -EF

FG = 6 -2

FG = 4

Step-by-step explanation:

3 0
4 years ago
Two vertical poles of lengths 11 ft and 14 ft stand 16 ft apart. A cable reaches from the top of one pole to some point on the g
Alex17521 [72]

We are given

total length of cable is 30 feet

and this cable is on hypotenuse sides of the triangles

so, we can draw triangle as

Let's assume those hypotenuse as 'a' and 'b'

so, we will have

a+b=30

now, we can find 'a' and 'b' from triangle

Smaller triangle:

a=\sqrt{x^2+11^2}

Larger triangle:

b=\sqrt{(16-x)^2+14^2}

we know that

a+b=30

so, we can plug this value

and we get

\sqrt{x^2+11^2}+\sqrt{(16-x)^2+14^2} =30

now, we can solve for x

\left(\sqrt{x^2+11^2}\right)^2=\left(30-\sqrt{\left(16-x\right)^2+14^2}\right)^2

32x-1231=-60\sqrt{x^2-32x+452}

1024x^2-78784x+1515361=3600x^2-115200x+1627200

now, we can use quadratic formula

we get

x=\frac{-\sqrt{36416^2-1152389056}+36416}{5152},\:x=\frac{\sqrt{36416^2-1152389056}+36416}{5152}

x=4.510,x=9.627

so,

The point should be located 4.510 feet , 9.627 feet from the smaller pole to use 30 feet cable............Answer

6 0
3 years ago
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