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3 years ago

Please help i dont understand how to solve this problem parallel to y=3/2+4 and through (2,-3)

1 answer:

7 0

Parallel means it must have the same slope so assuming you meant y=3/2x+4 the slope will remain 3/2

Then you just plug in the coordinates they give you

-3=(3/2)(2)+b
-3=3+b

b=-6 (b is the y intercept)

Final answer: y=3/2x-6

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Find the area of the figure.

jasenka [17]

Divide into shapes that you can find the area of.....

you also have to cross out the 5 and the 4s because you will not need them

2×2= 4 sq. cm
2×2= 4 sq. cm
9×2 = 18 sq. cm

18 + 4 + 4 = 26 sq. cm

so the area is 26 sq. cm

6 0

3 years ago

PLEASE HELP I WILL GIVE BRIANLIEST 15 POINTS!!! What is the equation in slope-intercept form of the line that crosses the x-axis

harkovskaia [24]

Answer:

Choice D

Step-by-step explanation:

First we should find the slope of the equation, so since it's perpendicular to the other equation that means it's the opposite and the reciprocal of that slope. So the slope is $\frac{9}{4}$ .

Now we have to find the y-intercept. We already know the x-intercept, so we could use that to find the y-intercept. For that we need to know the slope and one ordered pair, which is (36,0). Then we plug into this formula $y=mx+b$ .

$y=mx+b\\0=\frac{9}{4}(36)+b\\0=81+b\\b=-81$

So now that we found the y-intercept we just have to put it all together....

$y=\frac{9}{4}x-81$

8 0

3 years ago

What is 437 rounded to the nearest whole number

arsen [322]

Answer:

437

437 is a whole number itself, so it would be 437.

<em>Hope that helps!</em>

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

CAN SOMEONE PLEASE JUST ANSWER THIS ASAP FOR BRAINLIEST!!!

Nina [5.8K]

Answer:

Im pretty sure that the answer is a.

5 0

3 years ago

Write the given expression in terms of x and y only. tan(sin^-1(x)+cos^-1(y))

Softa [21]

Answer:

[xy + √(1−x²) √(1−y²)] / [y √(1−x²) − x √(1−y²)]

Step-by-step explanation:

tan(sin⁻¹x + cos⁻¹y)

Use angle sum formula:

[tan(sin⁻¹x) + tan(cos⁻¹y)] / [1 − tan(sin⁻¹x) tan(cos⁻¹y)]

To evaluate these expressions, I suggest drawing right triangles.

For example, let's draw a triangle where x is the side opposite of angle θ, and the hypotenuse is 1. Therefore:

sin θ = x/1

θ = sin⁻¹x

Using Pythagorean theorem, the adjacent side is √(1−x²). Therefore:

tan θ = x / √(1−x²)

tan(sin⁻¹x) = x / √(1−x²)

Draw a new triangle. This time we'll make y the adjacent side to angle θ.

cos θ = y/1

θ = cos⁻¹y

Using Pythagorean theorem, the opposite side is √(1−y²). Therefore:

tan θ = √(1−y²) / y

tan(cos⁻¹y) = √(1−y²) / y

Substituting:

[x / √(1−x²) + √(1−y²) / y] / [1 − x / √(1−x²) × √(1−y²) / y]

Multiply top and bottom by √(1−x²).

[x + √(1−x²) √(1−y²) / y] / [√(1−x²) − x × √(1−y²) / y]

Multiply top and bottom by y.

[xy + √(1−x²) √(1−y²)] / [y √(1−x²) − x √(1−y²)]

3 0

3 years ago