Will give brainliest don’t worry about the bottom
1 answer:
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Answer:
Step-by-step explanation:
The slope of a perpendicular line will always be the NEGATIVE RECIPROCAL of the slope of the original line.
y=2x+5
Because this equation is organized in slope-intercept form, y=mx+b, we can identify the slope of the original line is 2. The negative reciprocal of 2 is . Therefore, the slope of the perpendicular line is
. So far, our equation looks like this:
Now, we must solve for b, the y-intercept of this line. To do that, we can plug in the given point (-2,8) and solve for b:
Subtract both sides by 1 to isolate b
Therefore, the y-intercept of this line is 7.
After plugging both the slope and the y-intercept into y=mx+b, we get:
I hope this helps!
Answer:
B. (-6, -9)
D. (12, 3)
Step-by-step explanation:
y=mx+b is the format for this problem.
2/3 is m and -5 is b
The b is the y-intercept which is the point where the line crosses from one side of the graph to the other horizontally. You can see at -5, that is where that happens.
Then, to find the second point, you would move the -5 up 2 and right 3 points because the slope is 2/3.
You can then look at another point of the graph to find (-6, -9)
*Changed my answer from just B to B and D
