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kompoz [17]
3 years ago
13

Find the value of x in the triangle shown

Mathematics
2 answers:
german3 years ago
4 0

Answer : would be 5

Because a triangle that has a sequence of the number 3 & 4, or 3 & 5, or 4 & 5 will always consider of the number 3,4 and 5.

Also if te triangle did consist of different numbers the Pythagorean theorem ( a^2 + b^2 = c^2 ) can be use.

So in this case it’ll be 3^2 + 4^2 = c^2

9 + 16 = c^2

25 = c^ 2

Then we square root both sides and the answe will be : 5 = c

Mrrafil [7]3 years ago
3 0

Answer:

5

Step-by-step explanation:

you need to use the Pythagorean theorem

a^2+b^2=c^2

a&b=sides

c=hypotonuse

plug the side values into the equation

4^2+3^2=c^2

16+9=c^2

25=c^2

you have to square root 25 to find c itself

c=5

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<h3><u>Solution:- </u></h3>

Let the number to be added be A

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\begin{gathered}\implies\quad \sf −5x^3 + 4x − 3  + A = x^2 − x − 1 \\\end{gathered}

Transposing (−5x³+ 4x − 3 ) to other side-

\begin{gathered}\\\implies\quad \sf   A = x^2 − x − 1 -( −5x^3 + 4x − 3) \\\end{gathered}

Remember if there is a -ve sign before a bracket the signs of whole of the terms changes on opening bracket

\begin{gathered}\\\implies\quad \sf   A = x^2 − x − 1 + 5x^3 - 4x + 3\\\end{gathered}

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\begin{gathered}\\\implies\quad \sf   A = 5x^3 +x^2 - x -4x +3 -1  \\\end{gathered}

\begin{gathered}\\\implies\quad \sf   A = 5x^3 +x^2 -5x +2 \\\end{gathered}

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