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kompoz [17]
3 years ago
13

Find the value of x in the triangle shown

Mathematics
2 answers:
german3 years ago
4 0

Answer : would be 5

Because a triangle that has a sequence of the number 3 & 4, or 3 & 5, or 4 & 5 will always consider of the number 3,4 and 5.

Also if te triangle did consist of different numbers the Pythagorean theorem ( a^2 + b^2 = c^2 ) can be use.

So in this case it’ll be 3^2 + 4^2 = c^2

9 + 16 = c^2

25 = c^ 2

Then we square root both sides and the answe will be : 5 = c

Mrrafil [7]3 years ago
3 0

Answer:

5

Step-by-step explanation:

you need to use the Pythagorean theorem

a^2+b^2=c^2

a&b=sides

c=hypotonuse

plug the side values into the equation

4^2+3^2=c^2

16+9=c^2

25=c^2

you have to square root 25 to find c itself

c=5

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If a cyclist increases his speed by 3 miles per hour, he can reduce the time required for a 6 mile trip by 10 minutes. What is t
raketka [301]

Answer:

Slower speed = 9 mph

Step-by-step explanation:

Let the initial speed (slower speed) = s mph

Speed 's' = \frac{\text{Distance}}{\text{Time}}

            s = \frac{6}{t} -------(1)

If the cyclist increases the speed by 3 mph then the final speed = (s + 3) mph

He can reduce the time 't' by 10 minutes (\frac{1}{6} hours)

Now, (s + 3) = \frac{6}{t-\frac{1}{6}}

s + 3 = \frac{36}{6t-1} --------(2)

Substitute the value of 's' from equation (1) to the equation (2).

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6t² - t - 2 = 0

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From equation (1),

s = \frac{6}{\frac{2}{3}}

s = 9 miles per hour.

Slower speed = 9 mph is the answer.

6 0
3 years ago
Evaluate the expression when c=21 and d=4.<br> c-5d
vekshin1

\huge \boxed{\mathfrak{Question} \downarrow}

  • Evaluate the expression when c = 21 and d = 4, c - 5d = ?

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

Given,

  • c = 21
  • d = 4
  • c - 5d = ?

Let's solve it now :-

\sf \: c - 5d \\  \\  \sf \: Substitute \: the \: values \: of \: c \: and \: d \\  \\ \sf c - 5d \\  \rightarrow \sf(21) - 5(4) \\ \sf  \rightarrow21 - 20 \\  =    \boxed{\boxed{\bf \: 1}}

  • The value of the expression is <em><u>1</u></em><em><u>.</u></em>
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