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olga55 [171]
4 years ago
9

Which two whole numbers lies between the square root of 10

Mathematics
2 answers:
omeli [17]4 years ago
7 0

3 > √10 > 4

the answer would be 3 & 4

pantera1 [17]4 years ago
4 0

Answer: 3 & 4

Step-by-step explanation:

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It takes Alisa 16 months to grow her hair 8 inches.
3 0
4 years ago
I WILL GIVE BRAINLIEST TO BEST EXPLANATION!! How many 6-digit numbers, formed using each digit from 1 to 6 exactly once, are div
wolverine [178]

Answer:

There are 360 such numbers.

Step-by-step explanation:

The number of 6-digit numbers, formed using each digit from 1 to 6 excactly once, means we can have numbers like

123456, 123465, 123546,123564,.... 654321

The number of such numbers is given by 6! because we have a choice of 6 numbers for the first digit, 5 left for the next, ... until the last digit has only one choice.

6! = 6*5*4*3*2*1 = 720

We know that 1+2+3+4+5+6 = 21 is divisible by three, so all 720 numbers are divisible by 3.

However, to be divisible by six, we need a number divisible by three AND divisible by two.

Thus, out of the 720 numbers, we need count only the even numbers, which are exact half of the 720, or 360.

Therefore there are 360 6-digit numbers, formed using each digit from 1 to 6 exactly once, are divisible by 6.

4 0
3 years ago
Read 2 more answers
Explain how complex fractions can be used to solve problems involving ratios
adelina 88 [10]
Well, if you simplify complex fractions, they essentially turn into a ratio and a simple fraction, which you can multiply out if needed to , for example, separate a variable
4 0
4 years ago
At most, how many unique roots will a third-degree polynomial function have?
beks73 [17]

The fundamental theorem of algebra states that a polynomial with degree n has at most n solutions. The "at most" depends on the fact that the solutions might not all be real number.

In fact, if you use complex number, then a polynomial with degree n has exactly n roots.

So, in particular, a third-degree polynomial can have at most 3 roots.

In fact, in general, if the polynomial p(x) has solutions x_1,\ x_2,\ldots x_n, then you can factor it as

p(x) = (x-x_1)(x-x_2)\ldots (x-x_n)

So, a third-degree polynomial can't have 4 (or more) solutions, because otherwise you could write it as

p(x)=(x-x_1)(x-x_2)(x-x_3)(x-x_4)

But this is a fourth-degree polynomial.

7 0
3 years ago
-3x=2x+19 solve ​pls
nevsk [136]

Answer:

-19/5

Step-by-step explanation:

2x+3x+19=0

5x=-19

x=-19/5

7 0
3 years ago
Read 2 more answers
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