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Anettt [7]
3 years ago
10

Please Help. Write an equation of the line that passes through (1,2) and is perpendicular to the line

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
6 0

Answer:

y=\frac{1}{3}x+\frac{5}{3}

Step-by-step explanation:

  • Slope of y=-3x-4 is the m of the general equation y=mx+b which -3
  • The slope a line perpendicular to this line is <em>the number that if multiplied with -3 will give us -1</em>  so that \frac{1}{3}
  • With that slope and the point (1,2) use the formula
  • y-y_1=m(x-x_1)\\y-(2)=\frac{1}{3} (x-(1))\\y-2=\frac{1}{3}x-\frac{1}{3}\\y=\frac{1}{3}x+\frac{5}{3}
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Andrew has 20 more goldfish than Todd .together they have 80 goldfish how many goldfish does each boy have
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Answer:

Andrew 50

todd 30

Step-by-step explanation:

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3 years ago
-2,4, and 6. What would be the opposites of each of those points?
ss7ja [257]

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Step-by-step explanation:

3 0
3 years ago
A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 449 gram setting. It is
stealth61 [152]

Answer:

We accetp  H₀

Step-by-step explanation:

Information:

Normal distribution  

Population mean      =   μ₀  = 449

Population standard deviation  σ   unknown

Sample size   n  =  23        n < 30    we use t-student test

so   n  =  23    degree of fredom   df = n  - 1  df  = 23- 1   df = 22

Sample mean    μ =  448

Sample standard deviation   s  =  20

Significance level  α  =  0,05  

1.-Hypothesis Test

Null hypothesis                               H₀     μ₀  =  449

Alternative hypothesis                    Hₐ     μ₀  ≠  449

Problem statement ask for determine decision rule for rejecting the null hypothesis. For rejecting the null hypothesis we have to  get an statistic parameter wich implies  that μ is bigger or smaller than μ₀

2.-Significance level   α  =  0,05  ;  as we have a two tail test

α/2    =  0,025

Then from t - student table for  df =  22   and 0,025 (two tail-test)

t(c)  =  ±  2.074

3.- Compute  t(s)

t(s)   =  (  μ  -  μ₀ )  /  s /√n

plugging in values

t(s)   =  (448  -  449) /  20 /√23    ⇒   t(s)   =  -  1*√23 /20

t(s)   =  - 0.2398

4.-Compare t(c)   and  t(s)

t(s)  <  t(c)         - 0.2398  <  - 2.074

Therefore  t(s)  in inside acceptance region.  We accept  H₀

7 0
4 years ago
HURRY PLEASE!!
Olin [163]

280 my dudes.


55=arc Ab = arc ED

CD = 25

25 + 55 = 80

360-80

280 = arc EAC

7 0
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