Question

Please Help. Write an equation of the line that passes through (1,2) and is perpendicular to the line

Answer 1

Answer:

$y=\frac{1}{3}x+\frac{5}{3}$

Step-by-step explanation:

• Slope of $y=-3x-4$ is the m of the general equation $y=mx+b$ which $-3$
• The slope a line perpendicular to this line is the number that if multiplied with -3 will give us -1  so that $\frac{1}{3}$
• With that slope and the point $(1,2)$ use the formula
• $y-y_1=m(x-x_1)\\y-(2)=\frac{1}{3} (x-(1))\\y-2=\frac{1}{3}x-\frac{1}{3}\\y=\frac{1}{3}x+\frac{5}{3}$