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2 years ago

Which of the following is true?

Mathematics

1 answer:

gtnhenbr [62]2 years ago

6 0

Answer:

C..... I think it is a answer

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If a = 2 and b = 5, then the value of the expression 3a - 2b + 5 is

sweet [91]

Answer:

here is your answer!!!

Step-by-step explanation:

mark as brainliest and drop some thanks!!

8 0

2 years ago

If the length of AC equals 18, what is the length of the midsection DE

Free_Kalibri [48]

Answer:

The length of the midsegment is 9 ⇒ (B)

Step-by-step explanation:

In a triangle,

The midsegment is the segment which joining the midpoints of two opposite sides of it

The length of the midsegment is half the length of the third side in the triangle which opposite to it

Let us use this rule to solve our question

In Δ AC

∵ DE is the midsegment of it

∵ DE is opposite to the side AC

∴ The length of DE = 1/2 the length of AC

∵ The length of AC = 18

∴ The length of DE = 1/2 × 18

∴ The length of DE = 9

∴ The length of the midsegment is 9

The correct answer is B

7 0

3 years ago

What are the solutions of the equation?

Olegator [25]

The correct answer would be 41

7 0

2 years ago

#12 with explanation please

4vir4ik [10]

Answer:

30.01 units

Step-by-step explanation:

Given vertices WXYZ:

W(-4,5), X(2,4), Y(3, -4), Z(-1, -6)

Perimeter is the sum of the side length.

Use distance formula to find each side:

WX = $\sqrt{(2+4)^2+(4-5)^2} =\sqrt{37}$ ≈ 6.08
XY = $\sqrt{(3-2)^2+(-4-4)^2} =\sqrt{65}$ ≈ 8.06
YZ = $\sqrt{(-1-3)^2+(-6+4)^2} =\sqrt{20}$ ≈ 4.47
WZ = $\sqrt{(-1+4)^2+(-6-5)^2} =\sqrt{130}$ $\sqrt{(-1+4)^2+(-6-5)^2}=\sqrt{130}$ ≈ 11.40

Find perimeter:

P = 6.08 + 8.06 + 4.47 + 11.40 = 30.01 units

7 0

2 years ago

How many litres of milk can be put in six hemispherical bowl each of diameter 35cm

Lesechka [4]

Answer:

Approximately 67.348 litres can be put in six hemispherical bowl with a diameter of 35 centimetres.

Step-by-step explanation:

The volume of a hemisphere ( $V$ ), measured in cubic centimetres, is obtained from this formula:

$V = \frac{2\pi}{3}\cdot R^{3}$

Where $R$ is the radius of the hemisphere, measured in centimetres.

We know that radius is the half of the diameter ( $D$ ), measured in centimetres, then:

$R = 0.5\cdot D$

( $D = 35\,cm$ )

$R = 0.5\cdot (35\,cm)$

$R = 17.5\,cm$

Now, we get the volume of each hemispherical bowl:

$V = \frac{2\pi}{3} \cdot (17.5\,cm)^{3}$

$V \approx 11224.649\,cm^{3}$

The total volume of six hemispherical bowl is:

$V_{T} = 6\cdot V$

$V_{T}= 6\cdot (11224.649\,cm^{3})$

$V_{T} = 67347.894\,cm^{3}$

From Physics we know that 1 litre equals 1000 cubic centimetres. Then:

$V_{T} = 67.348\,L$

Approximately 67.348 litres can be put in six hemispherical bowl with a diameter of 35 centimetres.

3 0

3 years ago