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2 years ago

What are the x- and y- intercepts of the graph of 9x-3y = 18?

Mathematics

1 answer:

sineoko [7]2 years ago

3 0

Step-by-step explanation:

9x - 3y = 18

Solve for y:

1. 3y= 9x + 18

2. y= 3x + 6 (This is the equation you will graph)

To graph:

Make a table for y = 3x +6.

If x =0, y=6

If x =1, y=9

If x =-1, y=3

You could get as many points as you like, however you need at least TWO, to be able to draw the line.

You might be interested in

If 10 pencils and 7 erasers cost $4.23 and 3 pencils and 1 eraser cost $0.95, what is the cost of 2 erasers?

QveST [7]

Answer: $0.58

Step-by-step explanation:

Let x represent pencil and y represent eraser

10x + 7y = 4.23 → 1(10x + 7y = 4.23) → 10x + 7y = 4.23

3x + y = 0.95 → -3(3x + y = 0.95) → -21x - 7y = -6.65

-11x = -2.42

÷-11 ÷-11

x = 0.22

3x + y = 0.95

3(0.22) + y = 0.95

0.66 + y = 0.95

y = 0.29

2y = 2(0.29) = 0.58

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Csf%20%5Csqrt%7B12%7D%20%5Ctimes%20%5Csqrt%7B12%7D" id="TexFormula1" title="\sf \sqrt{12} \t

Darina [25.2K]

Answer:

$12$

Step-by-step explanation:

$\sqrt{12} \times\sqrt{12}$

$\mathrm{Apply\:radical\:rule}:\quad \sqrt{a}\sqrt{a}=a,\:\quad \:a\ge 0$

$\sqrt{12}\sqrt{12}=12$

$=12$

7 0

2 years ago

A bird catches a fish flies 100 yards upward in a straight line and then drops the fish the fish Atlanta at a spot that is 50 ya

labwork [276]

Cos(x) = 50/100

part a) x= 60°
part b) height is 86.60254040

4 0

3 years ago

Slope of a line perpendicular to the line whose equation is 3x-3y=-63

ivanzaharov [21]

Answer:

slope perpendicular= -1

Step-by-step explanation:

3x-3y=-63

-3y=-3x-63 divide both sides by -3

y=1x+21

Perpendicular lines have slopes that are the opposite of the reciprocal of each other

3 0

3 years ago

Consider the implicit differential equation <img src="https://tex.z-dn.net/?f=%2849%20y%5E%7B3%7D%20%2B%2045%20xy%29%20dx%20%2B%

BaLLatris [955]

We're looking for an integrating factor $\mu(x,y)=x^py^q$ such that

$\mu\underbrace{(49y^3+45xy)}_M\,\mathrm dx+\mu\underbrace{(98xy^2+50x^2)}_N\,\mathrm dy=0$

is exact, which would require that

$(\mu M)_y=(\mu N)_x$
$(49x^py^{q+3}+45x^{p+1}y^{q+1})_y=(98x^{p+1}y^{q+2}+50x^{p+2}y^q)_x$
$49(q+3)x^py^{q+2}+45(q+1)x^{p+1}y^q=98(p+1)x^py^{q+2}+50(p+2)x^{p+1}y^q$
$\implies\begin{cases}49(q+3)=98(p+1)\\45(q+1)=50(p+2)\end{cases}\implies p=\dfrac52,q=4$

You can verify that $(\mu M)_y=(\mu N)_x$ if you'd like. With the ODE now exact, we have a solution $F(x,y)=C$ such that

$F_x=\mu M$
$F=\displaystyle\int(49y^3+45xy)x^{5/2}y^4\,\mathrm dx$
$F=10x^{9/2}y^5+14x^{7/2}y^7+f(y)$

$F_y=\mu N$
$50x^{9/2}y^4+98x^{7/2}y^6+f'(y)=98x^{7/2}y^2+50x^{9/2}y^4$
$f'(y)=0$
$\implies f(y)=C$

and so the general solution is

$F(x,y)=10x^{9/2}y^5+14x^{7/2}y^7=C$

8 0

3 years ago