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Nana76 [90]
3 years ago
10

Two butterflies simultaneously leave an aster flowerbed and fly to a rose flowerbed. One butterfly flies 10 m/min faster than th

e other, and so lands on a rose 1 minute earlier. Find the speed of each butterfly if the flowerbeds are 560m apart
Mathematics
1 answer:
Liula [17]3 years ago
8 0

Answer:

70 and 80

Step-by-step explanation:

Use the STD table, 560 is the distance, x and x+10 are the speeds, 560/x and 560/x+10 are the times. Make the equation 1+560/x+10=560/x and do the math aight.

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Step-by-step explanation:

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3 years ago
A quantity with an initial value of 6200 decays continuously at a rate of 5.5% per month. What is the value of the quantity afte
ELEN [110]

Answer:

410.32

Step-by-step explanation:

Given that the initial quantity, Q= 6200

Decay rate, r = 5.5% per month

So, the value of quantity after 1 month, q_1 = Q- r \times Q

q_1 = Q(1-r)\cdots(i)

The value of quantity after 2 months, q_2 = q_1- r \times q_1

q_2 = q_1(1-r)

From equation (i)

q_2=Q(1-r)(1-r)  \\\\q_2=Q(1-r)^2\cdots(ii)

The value of quantity after 3 months, q_3 = q_2- r \times q_2

q_3 = q_2(1-r)

From equation (ii)

q_3=Q(1-r)^2(1-r)

q_3=Q(1-r)^3

Similarly, the value of quantity after n months,

q_n= Q(1- r)^n

As 4 years = 48 months, so puttion n=48 to get the value of quantity after 4 years, we have,

q_{48}=Q(1-r)^{48}

Putting Q=6200 and r=5.5%=0.055, we have

q_{48}=6200(1-0.055)^{48} \\\\q_{48}=410.32

Hence, the value of quantity after 4 years is 410.32.

4 0
3 years ago
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Hope this helps :) 
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GaryK [48]
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Answer: ans is 288 (A)

Step-by-step explanation:

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