3x7x7x7x7 in index notation 2x9x9x9x2x9plz helpthx
2 answers:
Answer:
The Index notation for 3x7x7x7x7 is:
The Index notation for 2x9x9x9x2x9 is:
Step-by-step explanation:
Consider the provided number.
3×7×7×7×7 and 2×9×9×9×2×9
We need to write the number in index notation.
Index notation is shortcut method of writing repeated multiplications by the same number.
Consider the number.
Here, 3 repeat 1 time and 7 repeat 4 times.
Thus, the Index notation is:
Consider the second number.
Here, 2 repeat 2 times and 9 repeat 4 times.
Thus, the Index notation is:
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Remark
This question likely should be done before the other one. What you are trying to do is give C a value. So you need to remember that C is always part of an indefinite integral.
y =
y = sin(x) - cos(x) + C
y(π) = sin(π) - cos(π) + C = 0
y(π) = 0 -(-1) + C = 0
y(π) = 1 + C = 0
C = - 1
y = sin(x) - cos(x) - 1 <<<<< Answer
Problem Two
Remember that
y( - e^3 ) = ln(|x|) + C = 0
y(-e^3) = ln(|-e^3|) + C = 0
y(-e^3) = 3 + C = 0
3 + C = 0
C = - 3
y = ln(|x|) - 3 <<<< Answer
This question likely should be done before the other one. What you are trying to do is give C a value. So you need to remember that C is always part of an indefinite integral.
y =
y = sin(x) - cos(x) + C
y(π) = sin(π) - cos(π) + C = 0
y(π) = 0 -(-1) + C = 0
y(π) = 1 + C = 0
C = - 1
y = sin(x) - cos(x) - 1 <<<<< Answer
Problem Two
Remember that
y( - e^3 ) = ln(|x|) + C = 0
y(-e^3) = ln(|-e^3|) + C = 0
y(-e^3) = 3 + C = 0
3 + C = 0
C = - 3
y = ln(|x|) - 3 <<<< Answer