Question

Unit 8: Right Triangles & Trigonometry Homework 2: Special Right Triangles

Answer 1

Answer:

17.

78\sqrt{3},\ 39\sqrt{3},\ 78\sqrt{3}

19.

6,\ 12,\ 12\sqrt{2}

Step-by-step explanation:

Answer 2

Answer:

17. z=39/sin45=$78/\sqrt{2}$

    y=39/tan60=$39/\sqrt{3}$

    x=y/sin60=$78/\sqrt{3}$

19. x=$6\sqrt{3}/tan60$=6

    y=2x=12

    z=$\sqrt{2}y=12\sqrt{2}$

Step-by-step explanation:

17.

because:sin45=39/z    

so:     z=39/sin45=$78/\sqrt{2}$

then: tan60=39/y

so:    y=39/tan60=$39/\sqrt{3}$

last:  sin60=y/x

so:    x=y/sin60=$78/\sqrt{3}$

19.

because: tan60=$6\sqrt{3}$/x

so:            x=$6\sqrt{3}/tan60$=6

then:        sin30=x/y

so:            y=x*sin30=2x=12

last:          sin45=y/z

so:            z=sin45*y=$\sqrt{2}y=12\sqrt{2}$