If a secant<span> and a </span><span>tangent of a circle </span><span>are drawn from a point outside the circle, then the product of the lengths of the secant and its external segment equals the square of the length of the tangent segment.
</span><span>
y</span>² = 7(15+7)
<span>y</span>² = 7*22
<span>y</span>² = 154
<span>y = </span>√154
<span>y = 12.4 </span>← to the nearest tenth<span>
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Answer:
-0.5
Step-by-step explanation:
Use the simultaneous equations method:
x - 4y = 6
3x + 4y = 10
Add these two equations together to cancel out 'y':
4x = 16
Divide both sides by 4:
x = 4
substitute this value into one of the equations:
(4) - 4y = 6
Subtract 4 from both sides:
- 4y = 2
Divide both sides by -4:
y = -0.5
goodluck!
The surface area of a sphere of radius r is A = 4π*r^3.
Since the radius in this case is 7 cm (half the 14 cm diameter), the area of this sphere is
A = 4π(7 cm)^2, or 196π cm^2.
Answer:
x = 48
Step-by-step explanation:
If the two angles are supplementary then their sum must be 180 degrees
x + 34 + 2x + 2 = 180
3x + 36 = 180 subtract 36 from both sides
3x = 144 divide both sides by 3
x = 48
