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OverLord2011 [107]
3 years ago
10

WILL GIVE 50 POINTS FOR CORRECT ANSWER ASAP AND WILL GIVE BRAINLIEST.

Mathematics
2 answers:
Rufina [12.5K]3 years ago
8 0

Answer:

(2, -1)

Step-by-step explanation:

because that's where the lines intersect

ladessa [460]3 years ago
8 0
(2,-1)

The solution is where the lines intersect
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If Upper X overbar equals 62​, Upper S equals 8​, and n equals 36​, and assuming that the population is normally​ distributed, c
marishachu [46]

Answer:

The 99% confidence interval would be given by (58.373;65.627)    

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=62 represent the sample mean

\mu population mean (variable of interest)

s=8 represent the sample standard deviation

n=36 represent the sample size  

Part a: Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=36-1=35

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,35)".And we see that t_{\alpha/2}=2.72

Now we have everything in order to replace into formula (1):

62-2.72\frac{8}{\sqrt{36}}=58.373    

62+2.72\frac{8}{\sqrt{36}}=65.627    

So on this case the 99% confidence interval would be given by (58.373;65.627)    

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

3 0
3 years ago
A florist is going to make a five flower arrangement from the following flowers: a lily, a rose, a carnation, a daisy, a dahlia,
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Here total available flowers are a lily,a rose , a carnation , a daisy, a dahlia and an iris that is 6 .

And florist is going to make a five flower arrangement from the given 6 flowers without selecting a daisy. SO he have a total of 5 flowers available .

Therefore required probability = 5/6

7 0
3 years ago
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= x ^{2}  - 3x - 18 \\  =x ^{2}  - (6 - 3)x - 18 \\  = x ^{2}  - 6x + 3x - 18 \\  = x(x - 6) + 3(x - 6)  \\ = (x - 6)(x + 3)

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Select the description that is true of the equation y=-5x+5 .
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y = (m)x + (b)
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