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scoundrel [369]
2 years ago
12

Evaluate the expression 7^2/ x^2 - 2 for x = 3

Mathematics
1 answer:
vovikov84 [41]2 years ago
4 0

Answer:

7

Step-by-step explanation:

7²/x²-2 when x=3

49/3²-2

49/9-2

49/7

answer=7

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Which side of XYZ is the longest? <br><br>A. xy<br>B. xz<br>C. yz<br>D. cannot be determined​
Eddi Din [679]

Answer:

the answer is x because its small

4 0
3 years ago
Could u help me <br><br>with this ​
AleksandrR [38]

Answer:

P = 7

Step-by-step explanation:

46+8=54

54-5=49

49÷7=P

5 0
3 years ago
Given: m∠A = m∠C = 90° AB ║ DC Prove: ∆ABD ≅ ∆CBD
Genrish500 [490]

Answer:

Angle-Angle-Side (AAS)

Step-by-step explanation:

Given triangles; ΔABD and ΔCBD

  <A = <C = 90^{0} (right angle property)

   AB ║ DC (given)

Then,

    DA ║ CB

   <B ≅ <D (congruent property)

    DB ≅ BD (similarity property)

    <D + <B = <B + <D (complementary angles, and property of triangles)

Therefore by Angle-Angle-Side (AAS),

                 ∆ABD ≅ ∆CBD

4 0
2 years ago
A shirt is originally priced at $24.50. The shirt goes on sale for 30% the original price. How much money, in dollars to the nea
ludmilkaskok [199]

Answer:

The final cost is 1.07($17.15) = $18.35

Step-by-step explanation:

If the discount is 30%, we can find the discounted price by taking 70% of the original price (since 100% - 30% = 70%).  Substitute the equivalent 0.70 to calculate the discount price:  0.70($24.50) = $17.15.  This is the discounted price.

The final cost is $17.15 times 1.07, which includes the discounted price plus the 7% tax.  That final cost is 1.07($17.15) = $18.35.

3 0
3 years ago
At time t=0 hours, a tank contains 3000 litres of water. Water leaks from the tank. At the end of every hour there is x% less wa
Margaret [11]

Answer:

x = 2; K = 0.98

Step-by-step explanation:

At time, t = 0, Volume of Water = 3,000 litres

After t hours , the Volume of water in the tank = Vt

At the end of every hour there is a x% less water in the tank then at the start of the hour

After 1 hour, volume of water left Vt = V1

V1 = 3,000 - 3000 × (x/100)

V1 = 3,000 - 30x

After 2 hours, Volume of water left is V2

V2 = (3,000 - 30 x) - (3,000 - 30 x) × (x/100)

V2 = (3,000 - 30 x) - (3000x - 30x²)/100

V2 = {100(3000 - 30x) - x(3000 - 30x)} /100

V2 = {(3000 - 30x)(100 - x)}/100

Recall, V2 = 2881.2

Therefore

{(3000 - 30x)(100 - x)}/100 = 2881.2

(3000 - 30x)(100 - x) = 288120

300000 - 3000 x - 3000 x + 30 x² = 288120

30 x ² - 6000 x + 11880 = 0

Dividing both sides by 30

x² - 200 x + 396=0

Factorizing:

(x -198)(x-2) = 0

x = 198 or x = 2

Since the percentage by which the water reduces cannot be greater than 100, x = 2 is chosen.

Step 2: Solving for k

Given that Vt=KtV0

K = Vt/V0

At t = 1

V1 = 3000 - 30x

V1 = 3000 - 30 × 2

V1 = 3000 - 60

V1 = 2940

K = 2940/3000

K = 0.98

5 0
3 years ago
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