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Marrrta [24]
3 years ago
14

Mr Suvillian is organizing items for the middle schools annual field trip. There are 8 classes at the school with 22 students in

each class. If Mr Sullivan wants to have 12 students on each team. How many students will be left over ?
Mathematics
1 answer:
Bas_tet [7]3 years ago
4 0

Answer: 8 left over

Step-by-step explanation: Take 8 classes and multiply by 22 students each. Divide that answer by 12 to see what you have left over.

8x22=176

176/12= 14 remainder of 8

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18,430! I hope this helps you out!
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3 years ago
At a football game, the ratio of men to women is 4:1 There are 9,000 people in total, and each ticket costs £10 Calculate the am
uranmaximum [27]

Answer:

£72000

Step-by-step explanation:

According to the Question,

  • Given, At a football game, the ratio of men to women is 4:1 & There are 9,000 people in total

Thus, 5 ⇒ 9000 People

So, 4 ⇒ 7200 People(Men)

      1 ⇒ 1800 People(Women)

  • And, each ticket costs £10

Thus, The amount of money made from tickets sold to men is 7200 total Men x £10 Per Ticket Cost ⇒ £72000.

4 0
2 years ago
Arc CD is One-fourth of the circumference of a circle. What is the radian measure of the central angle?
GalinKa [24]

Answer:

B--StartFraction pi Over 2 EndFraction radians

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What are the types of roots of the equation below?<br> - 81=0
Tju [1.3M]

Option B, that is Two Complex and Two Real which are x + 3, x - 3, x + 3i and x - 3i, are the types of roots of the equation x⁴ - 81 = 0. This can be obtained by finding root of the equation using algebraic identity.    

<h3>What are the types of roots of the equation below?</h3>

Here in the question it is given that,

  • the equation x⁴ - 81 = 0

By using algebraic identity, (a + b)(a - b) = a² - b², we get,  

⇒ x⁴ - 81 = 0                      

⇒ (x² +  9)(x² - 9) = 0

⇒ (x² + 9)(x² - 9) = 0

  1. (x² -  9) = (x² - 3²) = (x - 3)(x + 3) [using algebraic identity, (a + b)(a - b) = a² - b²]
  2. x² + 9 = 0 ⇒ x² = -9 ⇒ x = √-9 ⇒ x= √-1√9 ⇒x = ± 3i

⇒ (x² + 9) = (x - 3i)(x + 3i)

Now the equation becomes,

[(x - 3)(x + 3)][(x - 3i)(x + 3i)] = 0

Therefore x + 3, x - 3, x + 3i and x - 3i are the roots of the equation

To check whether the roots are correct multiply the roots with each other,

⇒ [(x - 3)(x + 3)][(x - 3i)(x + 3i)] = 0

⇒ [x² - 3x + 3x - 9][x² - 3xi + 3xi - 9i²] = 0

⇒ (x² +0x - 9)(x² +0xi - 9(- 1)) = 0

⇒ (x² - 9)(x² + 9) = 0

⇒ x⁴ - 9x² + 9x² - 81 = 0

⇒ x⁴ - 81 = 0

Hence Option B, that is Two Complex and Two Real which are x + 3, x - 3, x + 3i and x - 3i, are the types of roots of the equation x⁴ - 81 = 0.

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: What are the types of roots of the equation below?

x⁴ - 81 = 0

A) Four Complex

B) Two Complex and Two Real

C) Four Real

Learn more about roots of equation here:

brainly.com/question/26926523

#SPJ9

5 0
1 year ago
Show work for 694 divided by 3
tatuchka [14]

Answer: 231.3 repeating!

Step-by-step explanation: I used the calculator

8 0
2 years ago
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