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Korolek [52]
2 years ago
9

The transformations to the parent function of a quadratic equation are given below. write an equation of the new function in ver

tex form

Mathematics
1 answer:
musickatia [10]2 years ago
3 0

Answer:

<h2>11.f(x)=^2-3</h2>

Step-by-step explanation:

<h2>12.And slide everything five units down. So a over here that's negative three negative one. So if we slide at five you just down we go one two three four five and get here.</h2>

Hope it helps

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Please help I will give Brainliest please!
WITCHER [35]

Part (a)

The domain is the set of allowed x inputs of a function.

The graph shows that x = 0 is not allowed because of the vertical asymptote located here. It seems like any other x value is fine though.

<h3>Domain: set of all real numbers but x \ne 0</h3>

To write this in interval notation, we can say (-\infty, 0) \cup (0, \infty) which is the result of poking a hole at 0 on the real number line.

--------------

The range deals with the y values. The graph makes it seem like it stretches on forever in both up and down directions. If this is the case, then the range is the set of all real numbers.

<h3>Range: Set of all real numbers</h3>

In interval notation, we would say (-\infty, \infty) which is almost identical to the interval notation of the domain, except this time of course we aren't poking at hole at 0.

=======================================================

Part (b)

<h3>The x intercepts are x = -4 and x = 4</h3>

We can compact that to the notation x = \pm 4

These are the locations where the blue hyperbolic curve crosses the x axis.

=======================================================

Part (c)

<h3>Answer: There aren't any horizontal asymptotes in this graph.</h3>

Reason: The presence of an oblique asymptote cancels out any potential for a horizontal asymptote.

=======================================================

Part (d)

The vertical asymptote is located at x = 0, so the equation of the vertical asymptote is naturally x = 0. Every point on the vertical dashed line has an x coordinate of zero. The y coordinate can be anything you want.

<h3>Answer: x = 0 is the vertical asymptote</h3>

=======================================================

Part (e)

The oblique or slant asymptote is the diagonal dashed line.

It goes through (0,0) and (2,6)

The equation of the line through those points is y = 3x

If you were to zoom out on the graph (if possible), then you should notice the branches of the hyperbola stretch forever upward but they slowly should approach the "fencing" that is y = 3x. The same goes for the vertical asymptote as well of course.

<h3>Answer:  Oblique asymptote is y = 3x</h3>
5 0
2 years ago
5(3m+2)<br> 6(g+h)<br> 4d+8<br> 21p+35q<br> 18x+9y
aalyn [17]
<span>(a) 5(3m+2) = 15m + 10

(b) 6(g+h) = 6g + 6h

(c) 4d+8 = 4(d + 2)

(d) 21p+35q = 7(3p + 5q)

(e) 18x+9y = 9(2x + y)</span>
7 0
3 years ago
what is most likely true about the digital grandparents of students that attend fridgemont high? the results of the survey are s
Olenka [21]
More grandparents prefer hard copy over digital copy
3 0
2 years ago
Point A to point B: Walk 200 m north for 3 minutes. •
vampirchik [111]

Step-by-step explanation:

200 + 100 + 150 + 200 +150 = 800 m in total

8 min in total

you are going 100 m a minute or 6000 m an hour

6 0
2 years ago
Jazmin is completing an art project. She has two pieces of construction paper. The first piece is 44 inches wide and the second
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One piece of paper is 44 and the other is 33

she can cut each strip where it is 11 inches in width
4 0
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