Ask question

Ask question

All categories

2 years ago

10

Add (1.3t3 + 0.4t2 – 24t) + (8 – 18t + 0.6t2) For each term in the second polynomial, enter the letter showing where that term s

hould be placed to add the polynomials vertically.

1 answer:

nignag [31]2 years ago

8 0

Answer:

$(1.3t^3 + 0.4t^2 - 24t) + (8 - 18t + 0.6t^2) = 1.3t^3 + t^2 -42t + 8$

Step-by-step explanation:

Given

$(1.3t^3 + 0.4t^2 - 24t) + (8 - 18t + 0.6t^2)$

Required

Solve

We have:

$(1.3t^3 + 0.4t^2 - 24t) + (8 - 18t + 0.6t^2)$

Collect like terms

$1.3t^3 + 0.6t^2 + 0.4t^2 - 24t- 18t + 8$

$1.3t^3 + t^2 -42t + 8$

So:

$(1.3t^3 + 0.4t^2 - 24t) + (8 - 18t + 0.6t^2) = 1.3t^3 + t^2 -42t + 8$

You might be interested in

85% of 16,000,000 people in the Netherlands own a bike, and most of them ride every day. Which equation would you use to find ho

Scilla [17]

Answer:

Multiplication 0.85 X 16,000,000=13600000

Step-by-step explanation:

0.85 X 16,000,000=13600000

4 0

1 year ago

Find x? Nnnnnnnnnnnnnnnnnnnnnnn

coldgirl [10]

Cos(x) = 32/40 = 0.8 ⇒ x ≈ 37°

6 0

3 years ago

If M is the centroid of triangle GHI, HL=45, JI=63, and KG=60, find the missing measures

AysviL [449]

Answer:

Part a) $ML=15\ units$

Part b) $HM=30\ units$

Part c) $JM=21\ units$

Part d) $MI=42\ units$

Part e) $GM=40\ units$

Part f) $MK=20\ units$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

A <u><em>centroid</em></u> of a triangle is the point where the three medians of the triangle meet. A median of a triangle is a line segment from one vertex to the mid point on the opposite side of the triangle.

The centroid is located two thirds of the distance from any vertex of the triangle

Part a) Find ML

we have

$HL=45\ units$

we know that

$ML=\frac{1}{3}HL$

substitute the given value

$ML=\frac{1}{3}(45)$

$ML=15\ units$

Part b) Find HM

we have

$HL=45\ units$

we know that

$HM=\frac{2}{3}HL$

substitute the given value

$HM=\frac{2}{3}(45)$

$HM=30\ units$

Part c) Find JM

we have

$JI=63\ units$

we know that

$JM=\frac{1}{3}JI$

substitute the given value

$JM=\frac{1}{3}(63)$

$JM=21\ units$

Part d) Find MI

we have

$JI=63\ units$

we know that

$MI=\frac{2}{3}JI$

substitute the given value

$MI=\frac{2}{3}(63)$

$MI=42\ units$

Part e) Find GM

we have

$KG=60\ units$

we know that

$GM=\frac{2}{3}KG$

substitute the given value

$GM=\frac{2}{3}(60)$

$GM=40\ units$

Part f) Find MK

we have

$KG=60\ units$

we know that

$MK=\frac{1}{3}KG$

substitute the given value

$MK=\frac{1}{3}(60)$

$MK=20\ units$

6 0

3 years ago

Triangle ABC has vertices A(0, 2), B(x, 0), and C(0, -2). Determine the value of x that makes triangle ABC a regular triangle.

Jobisdone [24]

Answer:

$x = \sqrt{12 } = 2 \sqrt{3} \: or \\ x = - \sqrt{12} = - 2 \sqrt{3}$

Step-by-step explanation:

In order for the triangle to be a right one we need every side to be of the same length. see the photo for furyher explanation.

5 0

2 years ago

For the upcoming holiday season, Dorothy wants to mold 20 bars of chocolate into tiny pyramids. Each bar of chocolate contains 6

abruzzese [7]

Answer:

The largest number of pyramids she can make from 20 bars of chocolate is:

<u>A. 180</u>

Step-by-step explanation:

Firstly, you must find the volume of the 20 bars of chocolate, remember that each bar contains 6 cubic inches of chocolate (6 in^3), so:

Volume of the bars = 6 in^3 * 20
<u>Volume of the bars = 120 in^3</u>

Now, you must find the volume of each pyramid, using the next formula:

Volume of a pyramid = 1/3 B * h

Where:

<em>B = area of the square base.</em>

<em>h = height of the pyramid.</em>

How these values are given in the problem, we only replace the values in the formula:

Area of a pyramid = 1/3 (1 in^2) * 2 in
<u>Area of a pyramid = 2/3 in^3</u>

Finally, we divide the volume of the bars in the volume of each pyramid:

Total number of pyramids = 120 in^3 / 2/3 in^3
<u>Total number of pyramids = 180</u>

5 0

3 years ago