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3 years ago

I need help in math. I think it is x > 16

Mathematics

2 answers:

tatyana61 [14]3 years ago

3 0

Answer:

yes it is b

Step-by-step explanation:

goldenfox [79]3 years ago

3 0

Answer:

yes it is b.....

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The diameter of a circle is 2 centimeters. What is the circle's circumference?

leonid [27]

C=6.28cm
because C=2pi•r
so in this case C=2•3.14•1
which is C=2•3.14
and that leads to C=6.28cm

hope this helped

4 0

3 years ago

Compute: 245 * 1,493. Show your work.

sesenic [268]

0 + 0 + 5 = 5

0 + 2 + 6 = 8

6 + 7 + 4 = 17
Put the 7 in the appropriate column and carry the 1.

8 + 9 + 7 + 1(carried) = 25
Put the 5 in the appropriate column and carry the 2.

9 + 5 + 2(carried) = 16
Put the 6 in the appropriate column and carry the 1.

2 + 1(carried) = 3

So: 1493 × 245 = 365785

4 0

3 years ago

What would equal -1.11 when you divide by -4?

erik [133]

Answer:

x= -4.44

Step-by-step explanation:

4 0

3 years ago

N Example 3, the points are(0,3500) and (5,1750). Write an equation that represents the distance y (in feet) remaining after x m

Cerrena [4.2K]

Answer:

<h2>The time needed is 10 months.</h2>

Step-by-step explanation:

The given points are (0, 3500) and (5, 1750).

First, we use the formula below to find the slope of the line

$m=\frac{y_{2}-y_{1} }{x_{2} -x_{1} }=\frac{1750-3500}{5-0}=\frac{-1750}{5}=-350$

Which means the function is deacrasing with a ratio of 350 feet per month.

Now, we use the slope and one point to find the equation

$y-y_{1} =m(x-x_{1} )\\y-1750=-350(x-5)\\y=-350x+1750+1750\\y=-350x+3500$

This linear function shows that the situation started at the y-intecept (0, 3500), which means the month 0 had already 3500 feet. In other words, the total distance is 3500 feet. Now, the x-intercept will tell us the time needed to travel that distance.

$0=-350x+3500\\-3500=-350x\\x=\frac{-3500}{-350}\\ x=10$

Therefore, the time needed is 10 months.

3 0

3 years ago

A triangle has vertices at (1,10), (-5,2), and (7,2). What is its orthocenter. Show your work.

kondor19780726 [428]

Answer:

Question: What is the orthocenter of a triangle with the vertices (-1,2) (5,2) and (2,1)?

The coordinates of point A are (-1,2), point B are (5,2), and point C are (2,1).

The orthocent is the intersection of the three altitudes. An altitude goes from a vertex and is perpendicular to the line containing the opposite side.

In the coordinate plane the equations of the altitudes can be found and then a system of equations can be solved.

Altitude 1. From point C perpendicular to the line containing side AB.

Slope of line AB is 0 (horizontal line), a vertical line is perpendicular to a horizontal line. Thus, the equation of altitude 1 is x=2 .

Altitude 2. From point B perpendicular to the line containing side AC.

Slope of line AC is −13 , the slope of a line perpendicular to line AC is 3. The equation of altitude 2 is y=3x−13

Altitude 3. From point A perpendicular to the line containing side BC.

Slope of line BC is 13 , the slope of a line perpendicular to line BC is −3 . The equation of altitude 3 is y=−3x−1

The orthocenter is the point where all three altitudes intersect.

x=2

y=3x−13

y=−3x−1

Use substitution to solve the first two equations y=3(2)−13=−7

The orthocenter is the point (2,−7)

we did not need the third equation, but we can use it as a check, plug the coordinates into the third equation:

−7=−3(2)−1

−7=−6−1

−7=−7 it works.

3 0

3 years ago