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Rasek [7]
3 years ago
14

This 2 questions pls help

Mathematics
1 answer:
lesantik [10]3 years ago
5 0

Answer:

For the first picture: the answers A

For the second picture: it is also A

Step-by-step explanation:

I put each fraction into desmos for the second picture and the one that matched the image was A.

For the first image i picked A because 10 is a constant without a variable and is not a coefficient.

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True or false all points in quadrant 2 has a negative (x) value
ladessa [460]

Answer:

False, quadrant two has both negative and positive values.  

Hope I helped. Good luck on the assignment!

Step-by-step explanation:


4 0
4 years ago
2.48 rounded to the nearest cent
aleksklad [387]

Answer:

2

Step-by-step explanation:

.48 rounds down

.5 rounds up

8 0
3 years ago
Read 2 more answers
What is the measure of ZABD?<br> A. 329<br> B. 589<br> C. 640<br> D. 1489<br> E. 180
Step2247 [10]

Answer:

148

Step-by-step explanation:

a straight line is always 180 degrees. therefore if you subtract 32 from 180 you are left with 148 degrees.

hope this helps

6 0
3 years ago
Read 2 more answers
⊙O and ⊙P are given with centers (−2, 7) and (12, −1) and radii of lengths 5 and 12, respectively. Using similarity transformati
goldenfox [79]

Answer:

Whereby circle \bigodotP can be obtained from circle \bigodotO by applying the transformations of a translation of T₍₁₄, ₋₈₎ followed by a dilation by a scale factor of 2.4, \bigodotO is similar to \bigodotP

Step-by-step explanation:

The given center of the circle \bigodotO = (-2, 7)

The radius of \bigodotO, r₁ = 5

The given center of the circle \bigodotP = (12, -1)

The radius of \bigodotP, r₂ = 12

The similarity transformation to prove that \bigodotO and \bigodotP are similar are;

a) Move circle \bigodotO 14 units to the right and 8 units down to the point (12, -1)

b) Apply a scale of S.F. = r₂/r₁ = 12/5 = 2.4

Therefore, the radius of circle \bigodotO is increased by 2.4

We then obtain \bigodotO' with center at (12, -1) and radius r₃ = 2.4×5 = 12 which has the same center and radius as circle \bigodotP

∴ Circle \bigodotP can be obtained from circle \bigodotO by applying similarity transformation of translation of T₍₁₄, ₋₈₎ followed by a dilation by a scale factor of 2.4, \bigodotO is similar to \bigodotP.

7 0
3 years ago
Help plz plzzzzzzzzzzz ASAP
hjlf

Answer:

This is because the four triangles formed are all identical to each other.

7 0
3 years ago
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