Question

Assuming no other changes, what is the effect of doubling only the concentration of the alkyl halide in the above SN2 reaction?

Answer 1

Answer:

D) doubles the rate

Explanation:

The given reaction is :

$CH_3Br + OH^- \rightarrow CH_3OH+Br^-$

For the $SN^2$ reaction, the rate of reaction depends upon the concentration of both the $\text{alkyl halide}$ as well as the $\text{nucleophile.}$

That is the rate = $k[CH_3Br][OH^-]$

Now if the $[CH_3Br]$ becomes $2[CH_3Br]$, then the rate becomes double.

So the rate' is :

= $2k[CH_3Br][OH^-]$

= 2 x rate

Therefore, the answer is (D) doubles the rate.