Answer:
0.400 moles
Explanation:
Well, you know that one mole of ammonium chloride,
NH 4 Cl
, dissociates completely in aqueous solution to form one mole of ammonium cations,
NH + 4
, and one mole of chloride anions, Cl
−
.
Answer:
0.75 moles
Explanation:
S2 + 2O2 = 2SO2
From the reaction above,
We see that number of moles attached to S2 is 1 and number of moles attached to SO2 is 2.
Since we want to find how many moles of S2 are needed to produce 1.50 moles of SO2 gas
The answer is gotten by proportion;
Number of moles = 1/2 × 1.5 = 0.75 moles
Answer:
no of moles=mass in gm÷molar mass so let x be the mass in gm
4.5=x÷35.5×2
x=4.5×35.5×2 grams
x=319.5 gm
Explanation:
formula
Answer:
2Al(s) + 6HCl(aq) = 2AlCl3(aq) + 3H2(g)
Explanation:
The reaction is a displacement reaction.
The reaction does not commence immediately because the Al(aluminum) has Al2O3 (Aluminum oxide) which protect it from reacting with water.
It takes some time for the HCl (hydrochloric acid) to eat the coating, then the reaction proceed vigorously to produce hydrogen gas bubbles. Generally metals that are above hydrogen in the electrochemical series tend to displace Hydrogen from Hydrochloric acid. The more negative the electrochemical volts the more the tendency to lose electron. Metal above hydrogen have negative evolts while those below have positive evolts
Molarity of concentrated nitric acid = 15.9 M
Volume of the stock solution to be prepared = 500.0 mL
Concentration of the stock that is to be prepared = 0.750 M
Calculating moles from molarity and volume of stock:
Calculating volume of concentrated nitric acid to be taken for the preparation of stock solution:
Converting L to mL:
= 23.6 mL
Volume of distilled water to be added to 23.6 mL of 15.9 M nitric acid to get the given concentration = 5000.0mL-23.6mL=976.4 mL
Therefore, 976.4 mL distilled water is to be added to 23.6 mL of 15.9 M nitric acid solution to prepare 500.0 mL of 0.750M nitric acid.
