<h3>The cpi is currently 153. if a coffee maker costs $31.90 today, how much did one cost in 1983, to the nearest cent? a. $20.85 b. $21.20 <u>c. $26.60</u> d. $48.81</h3>
its C
Answer:
whats your question but thanks for the points
Step-by-step explanation:
Answer:
(3,-3)
Step-by-step explanation:
First you divide 2 out of the first equation and it turns into 5x+y=12.
Then you write one on top of the other so you can add them. It looks like:
5x + y = 12
-5x + y = -18
Then you add them together and the 5x's cancel each other out and you are left with 2y = -6
So then you divide both sides by 2 and get y = -3
Then you plug -3 into the second equation because it is simpler and get -5x - 3 = -18
So then you add three to both sides and get -5x = -15
And finally you divide both sides by -5 and get x=3
(L=17m and W=20m) and (L=40m and W=8.5m) are the possible dimensions (length and width) of the field given that the three sided fence has a length of 57m the area of the land is 340 square meters. This can be obtained by forming quadratic equation for the data.
<h3>Calculate the set of possible dimensions (length and width) of the field:</h3>
Let length be L and width be W.
Given that,
three sided fence has a length of 57m,
⇒ 2W + L = 57 m ⇒ L = 57 - 2W
the area of the land is 340 square meters
length × width = 340 ⇒ L × W = 340
(57 - 2W)W = 340
57W - 2W² = 340
2W² - 57W + 340 = 0
Solve for W using quadratic formula,
a = 2, b = -57, c = 340
W = (-b±√b²-4ac)/2a
= (57±√3249-2720)/4
= (57±√529)/4
= (57±23)/4
W = 20 m and W = 8.5 m
For W=20, L=57-2(20) = 17
For W=8.5, L=57-2(8.5) = 40
Hence (L=17m and W=20m) and (L=40m and W=8.5m) are the possible dimensions (length and width) of the field given that the three sided fence has a length of 57m the area of the land is 340 square meters.
Learn more about quadratic equations:
brainly.com/question/5975436
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I think the answer is 1/4 + 2x :)
