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natka813 [3]
2 years ago
10

Someone help me please with this algebra problem

Mathematics
1 answer:
aleksandr82 [10.1K]2 years ago
7 0

Answer:

4

Step-by-step explanation:

3r = 10 + 5s

r = 10

3(10) = 10 + 5s

30 = 10 + 5r

20 = 5r

r = 4

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Consider the triangle<br> Which shows the order of the angles from smallest to<br> largest?
NeX [460]

Answer: a triangle is a prism or a three angle  pyramid

Step-by-step explanation:

3 0
3 years ago
Find the values for a and b that would make the equality true.
Crank

Answer:

a = - 4, b = 5

Step-by-step explanation:

Expand the left side and compare the coefficients of like terms on the right side.

- 3(2x² + ax + b)

= - 6x² - 3ax - 3b

Comparing like terms with - 6x² + 12x - 15

x - term → - 3a = 12 ( divide both sides by - 3 )

                    a = - 4

constant term → - 3b = - 15 ( divide both sides by - 3 )

                               b = 5

6 0
3 years ago
What is the variance of a portfolio invested 21 percent each in a and b and 58 percent in c?
victus00 [196]
Given the following information:

\begin{tabular}&#10;{|p{1.5cm}|p{1.5cm}|p{1.2cm}|p{1.2cm}|p{1.2cm}|}&#10;\multicolumn{1}{|p{1.5cm}|}{State of economy}\multicolumn{1}{|p{2.6cm}|}{Probability of State of economy}\multicolumn{3}{|p{4.8cm}|}{Rate of Return if State Occurs}\\[1ex] &#10;\multicolumn{1}{|p{1.5cm}|}{}\multicolumn{1}{|p{2.6cm}|}{}\multicolumn{1}{|c|}{Stock A}&StockB&Stock C\\[2ex]&#10;\multicolumn{1}{|p{1.5cm}|}{Boom}\multicolumn{1}{|p{2.6cm}|}{0.66}\multicolumn{1}{|p{1.27cm}|}{0.09}&0.03&0.34\\&#10;\end{tabular}
\begin{tabular}&#10;{|p{1.5cm}|p{1.5cm}|p{1.2cm}|p{1.2cm}|p{1.2cm}|}&#10;\multicolumn{1}{|p{1.5cm}|}{Bust}\multicolumn{1}{|p{2.6cm}|}{0.34}\multicolumn{1}{|p{1.27cm}|}{0.23}&0.29&-0.14\\&#10;\end{tabular}

Part A:

The expected return on an equally weighted portfolio of these three stocks is given by:

0.66[0.33 (0.09) + 0.33 (0.03) + 0.33(0.34)] \\ +0.34[0.33 (0.23) + 0.33(0.29) +0.33(-0.14)] \\  \\ =0.66(0.0297 + 0.0099 + 0.1122)+0.34(0.0759+0.0957-0.0462) \\  \\ =0.66(0.1518)+0.34(0.1254)=0.1002+0.0426=0.1428=\bold{14.28\%}



Part B:

Value of a portfolio invested 21 percent each in A and B and 58 percent in C is given by

For boom: 0.21(0.09) + 0.21(0.03) + 0.58(0.34) = 0.0189 + 0.0063 + 0.1972 = 0.2224 or 22.24%.

For bust: = 0.21(0.23) + 0.21(0.29) + 0.58(-0.14) = 0.0483 + 0.0609 - 0.0812 = 0.028 or 2.8%

Expected return = 0.66(0.2224) + 0.34(0.028) = 0.1468 + 0.00952 = 0.1563 or 15.63%

The variance is given by

0.66(0.2224-0.1563)^2+0.34(0.028-0.1563)^2 \\  \\ =0.66(0.0661)^2+0.34(-0.1283)^2=0.66(0.00437)+0.34(0.01646) \\  \\ =0.00288+0.0056=\bold{0.00848}
4 0
3 years ago
$5 PAYPAL + BRAINLIEST TO ANSWER THS
expeople1 [14]

Answer:

Quadratic Equation:

3x^2=2x +5

\text{Standard Form: } 3x^2-2x-5=0

From the standard form of a Quadratic Function, we get:

a=3,\:b=-2,\:c=-5

Discriminant:

\Delta=\left(-2\right)^2-4\cdot \:3\left(-5\right)

\Delta=\left(-2\right)^2+4\cdot \:3\cdot \:5

\Delta=64

From the discriminant, we conclude that the equation will have two real solutions.

State that:

b^2-4ac

b^2-4ac =0:\text{The equation has 1 real solution}

b^2-4ac >0:\text{The equation has 2 real solutions}

By the way, solving the equation given:

$x=\frac{2\pm\sqrt{64}}{2\cdot \:3}$

$x=\frac{2\pm\sqrt{64}}{6}$

$x=\frac{2\pm8}{6}$

$x_{1} =\frac{10}{6}=\frac{5}{3}  $

$x_{2}=\frac{-6}{6} =-1$

5 0
3 years ago
Graph the following system of equations and find where they meet 3x + 5y = 36 y = 5x - 4
Over [174]

Answer:

[2,6]

Step-by-step explanation:

3x+5y=36

5x-4=y

3x+5(5x-4)=36

3x+25x-20=36

28x-20=36

28x=56

x=2

5x-4=y

5*2-4=y

10-4=y

6=y

4 0
3 years ago
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