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amid [387]
3 years ago
5

How do you write the equation in slope intercept form given (2,2) and (0,-2)?

Mathematics
1 answer:
Assoli18 [71]3 years ago
5 0

Answer:

y = 2x - 2

Step-by-step explanation:

The slope-intercept form of the equation of a line is

y = mx + b

where m is the slope, and b is the y-intercept.

y = mx + b

First we find the slope, m.

slope = (difference in y)/(difference in x)

It does not make a difference which point is first and which point is second in finding the differences, but you must do the x- and y-differences in the same order.

slope = (-2 - 2)/(0 - 2) = -4/(-2) = 2

The slope is 2, so m = 2, and now we have:

y = 2x + b

We need to find the value of b, the y-intercept.

We use one of the given points. Let's use (2, 2). We plug in 2 for x and 2 for y and solve for b.

2 = 2(2) + b

2 = 4 + b

-2 = b

b = -2

Now that we know the y-intercept is -2, we substitute b with -2.

y = 2x + b

y = 2x - 2

Answer: y = 2x - 2

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Answer:

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The correct option is: Option (B) \sum_{i=1}^{7} (5i-2)

Explanation:

First thing is that the difference between each number in the series with the next number is 5. It means it must be the multiple of 5. There are two options that contain multiples of 5: Option B and Option D. Now in the option D, the upper limit is 6. If we put 6 in the expression: 5(6)-2, the last term would be 28. However in the series given in the question, the last term is 33. Hence 5(7) - 2 = 35 - 2 = 33 which is Option B.

When i=1: 5(1)-2 = 3
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.
.
When i=7: 5(7)-2 = 35-2 = 33
Hence the correct option is (B).
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