3 years ago

Please help me with the answer u am behind a lot of work trying to avoid 0

Mathematics

1 answer:

Alecsey [184]3 years ago

4 0

Answer:

-3,4

Step-by-step explanation:

just follow up the other coordinates

You might be interested in

PLS PLSSS HURRY I NEED HELP

Sloan [31]

Answer:

look at the picture i have sent

5 0

2 years ago

Plz help i need it quick!!! simplify

ale4655 [162]

Answer:im not sure sorry

Step-by-step explanation:

3 0

3 years ago

Select the two values of x that are roots of this equation. 2x2 + 7x + 6 = 0

Anna007 [38]

Answer:

x = -3/2, -2

Step-by-step explanation:

2x^2 + 7x + 6 = 0

(2x + 3)(x + 2) = 0

(2x + 3)

2x = -3

x = -3/2

(x + 2)

x = -2

7 0

2 years ago

Read 2 more answers

A = √7 + √c and b = √63 + √d where c and d are positive integers.

mrs_skeptik [129]

Answer:

$\displaystyle a:b=\frac{1}{3}$

Step-by-step explanation:

<u>Ratios </u>

We are given the following relations:

$a=\sqrt{7}+\sqrt{c}\qquad \qquad[1]$

$b=\sqrt{63}+\sqrt{d}\qquad \qquad[2]$

$\displaystyle \frac{c}{d}=\frac{1}{9} \qquad \qquad [3]$

From [3]:

$9c=d$

Replacing into [2]:

$b=\sqrt{63}+\sqrt{9c}$

We can express 63=9*7:

$b=\sqrt{9*7}+\sqrt{9c}$

Taking the square root of 9:

$b=3\sqrt{7}+3\sqrt{c}$

Factoring:

$b=3(\sqrt{7}+\sqrt{c})$

Find the ration a:b:

$\displaystyle a:b=\frac{\sqrt{7}+\sqrt{c}}{3(\sqrt{7}+\sqrt{c})}$

Simplifying:

$\boxed{a:b=\frac{1}{3}}$

3 0

3 years ago

In the figure, Δ ABC Δ XYZ. What is the perimeter of ΔABC? Show your work.

slava [35]

Answer:

Step-by-step explanation:

∆ABC~ ∆XYZ

AB= 11 that is half of XY = 22

therefore XZ/2 = AC (base) = 32/2 = 16

and YZ /2 = BC(hypotenuse) = 44/2 = 22

(a= 11, b= 16, c= 22)

perimeter of a triangle

P = a+b+c

P= 11+16+22= 49

8 0

3 years ago