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valentina_108 [34]
3 years ago
14

PS 5.1- Solving

Mathematics
2 answers:
Alik [6]3 years ago
7 0

Answer:

84

Step-by-step explanation:

I'm pretty sure correct me if I'm wrong

vladimir2022 [97]3 years ago
4 0

Answer:

84

Step-by-step explanation:

108 / (7+2) = 12

7 x 12 = 84

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11)
kaheart [24]
B.) 20
If x goes from 2 to 4 it was multiplied by 2. you would do the same to the y. 10*2=20
5 0
3 years ago
Read 2 more answers
Find the 6th term of the geometric sequence whose common ratio is 3/2 and whose first term is 5
Fynjy0 [20]

Answer:

a(6) = 37.97

Step-by-step explanation:

If the first term a(1) is 5 and the common ratio r is 3/2, then the general formula for this geometric sequence is

a(n) = 5*r^(n - 1).

Thus, the 6th term is a(6) = 5*(3/2)^(6 - 1), or a(6) = 5(3/2)^5 = 37.97

5 0
3 years ago
Ivan purchased stock in a company at an initial price of $8 per share. The share value reached $18 after 10 days and then began
Butoxors [25]

The quadratic equation that best represents his model of the relationship between stock value and time is given by:

y = -0.0976(x - 10)^2 + 18, x \geq 0

The graph is given at the end of the answer.

<h3>What is the equation of a parabola given it’s vertex?</h3>

The equation of a quadratic function, of vertex (h,k), is given by:

y = a(x - h)^2 + k

In which a is the leading coefficient.

In this problem, the maximum value was a share value of $18 after 10 days, hence the vertex is:

(h,k) = (10,18).

Thus:

y = a(x - 10)^2 + 18

Since the initial price was of $8 per share, we have that:

8 = a(0 - 10)^2 + 18

-82a = 8

a = -\frac{8}{82}

a = -0.0976

Hence the equation is:

y = -0.0976(x - 10)^2 + 18, x \geq 0

At the end of the answer, the sketch of the graph is given.

More can be learned about quadratic equations at brainly.com/question/24737967

6 0
3 years ago
Please solve for the hypotenuse of a right triangle having legs 6 and 8. *
Arturiano [62]

Answer:

10

Step-by-step explanation:

6²+8²

=100

√100

=10

6 0
3 years ago
C+ax=dx<br><br><br>this one has all variables and no numbers
sergeinik [125]
That's OK, but you have not said which variable you want to solve it for.

<u>To solve for 'x':</u>
                                           <span>c + ax = dx

Subtract c from each side:    ax = dx - c

Subtract  dx  from each side:   ax - dx = -c

Factor the left side:                 x (a - d) = -c

Divide each side by (a - d) :      x = -c / (a - d)  or  <u>x = c / (d - a)</u> .

</span><span><u>To solve for 'c': </u>
</span><span>                                   c + ax = dx

Subtract  ax  from each side and factor:   <u>c  = x (d - a) </u>

</span><u>To solve for 'd': </u>
                                      <span>c + ax = dx

Divide each side by 'x':     d = c/x + a .

<u>To solve for 'a':</u>
</span><span><span>                                           c + ax = dx</span>

Subtract 'c' from each side:    ax = dx - c

Divide each side by 'x':          <u>a = d - c/x </u>.
.</span>
6 0
3 years ago
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