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posledela
1 year ago
11

15% of the students in the 6th grade wear glasses. If 12 students wear glasses, how can you determine the number of students in

the 6th grade? Explain your reasoning.
Mathematics
2 answers:
kodGreya [7K]1 year ago
7 0

Answer: There are 80 people in the 6th grade

Step-by-step explanation:

elena-14-01-66 [18.8K]1 year ago
3 0
There are 80 people. This is because you would take 12 and divide it by .15 to find the amount of students.
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What are some methods to finding the distance between A and B
Wittaler [7]
Are a and b two points on a line
If they are you can use the distance formula
6 0
3 years ago
Cesar, Carmen, and Dalila raised $95.34 for their tennis team. Carmen raised $12.12 less than Cesar, and Cesar raised $35 more t
NeTakaya

Answer:

Cesar's amount can be expressed by x + 12.12

Dalila's amount can be expressed as  x - 22.88

Step-by-step explanation:

If Carmen raised 12.12.less than Cesar, that means his amount is 12.12 more than hers so that is <u>x + 12.12</u> for <u>Cesar</u>.

If  Cesar raised 35 more than Dalila, her amount is Cesar's minus 35. Calculate: x+12.12 - 35. the difference is 22.88 less than x  so the amount for <u>Dalila is x- 22.88</u>

5 0
4 years ago
Can someone please help me
Evgesh-ka [11]

Answer:

UW ≈ 6.55 ≈ 7

Step-by-step explanation:

cos (35) = adjacent/hypotenuse

cos(35) = UW/VW

cos(35) = UW/8

8*cos(35) = UW

UW ≈ 6.55

Hope this helped! <3

7 0
3 years ago
Factor completely 36x^2 − 25.
sveticcg [70]
Hello there!

( (2^2*3^2x^2) -  25) \\ \\  Factoring:  \boxed{36x2-25} \\ \\ (PROOF): \\ \\  (A+B) * (A-B) = \\&#10;         A2 - AB + BA - B2 = \\&#10;         A2 - AB + AB - B2 =  \\&#10;         A2 - B2 \\ \\

Your final answer would be (<span> (6x + 5) • (6x - 5)).

Your correct answer would be (option d).

I hope this helps you!</span>
4 0
3 years ago
Read 2 more answers
A school has 1800 students and 1800 light bulbs, each with a pull cord and all in a row. All the lights start out off. The first
Gnom [1K]

<u>Solution-</u>

A school has 1800 students and 1800 light bulbs, each with a pull cord and all in a row.

As all the lights start out off, in the first pass all bulbs will be turned on.

In the second pass all the multiples of 2 will be off and rest will be turned on.

In the third pass all the multiples of 3 will be off, but the common multiple of 2 and 3 will be on along with the rest. i.e all the multiples of 6 will be turned on along with the rest.

In the fourth pass 4th light bulb will be turned on and so does all the multiples of 4.

But, in the sixth pass the 6th light bulb will be turned off as it was on after the third pass.

This pattern can observed that when a number has odd number of factors then only it can stay on till the last pass.

1 = 1

2 = 1, 2

3 = 1, 3

<u>4 = 1, 2, 4</u>

5 = 1, 5

6 = 1, 2, 3, 6

7 = 1, 7

8 = 1, 2, 4, 8

9 = 1, 3, 9

10 = 1, 2, 5, 10

11 = 1, 11

12 = 1, 2, 3, 4, 6, 12

13 = 1, 13

14 = 1, 2, 7, 14

15 = 1, 3, 5, 15

16 = 1, 2, 4, 8, 16

so on.....

The numbers who have odd number of factors are the perfect squares.

So calculating the number of perfect squares upto 1800 will give the number of light bulbs that will stay on.

As,  \sqrt{1800} =42.42  , so 42 perfect squared numbers are there which are less than 1800.

∴ 42 light bulbs will end up in the on position. And there position is given in the attached table.

7 0
3 years ago
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