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o-na [289]
3 years ago
11

Anyone know this ...

Mathematics
2 answers:
olasank [31]3 years ago
8 0
It should be AA c: ✌️
Natalka [10]3 years ago
5 0
The answer to this question should be AA c
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How to tell if a table is a exponential decay function an exponential growth function or neither
aliya0001 [1]

Answer:

Exponential function: a*b^x

if B is less than 1, it is a decay function

if B is more than 1, then it is a growth function  

if B is 0, then the function neither decreases nor increases

Example 1: 100*0.14^x

The y-intercept is decreasing by 86%

Example 2: 3000*1.14^x

The y-intercept is increasing by 14%

Example 3: 400*0

The y-intercept is neither decreasing nor increasing

Going back to the function, <u>a</u> is the y-intercept, and <u>b</u> is the rate

<u>I hope this will help you, I just started to learn about exponential functions..</u>

5 0
2 years ago
Which expression is equivalent in to the given expression? Assume the denominator does not equal zero.
marusya05 [52]

The equivalent expression of 14r^4y^6/7r^8y^2 is 2y^4/r^4

<h3>How to determine the equivalent function?</h3>

The expression is given as:

14r^4y^6/7r^8y^2

Start by dividing 14 by 7

2r^4y^6/r^8y^2

Next divide y^6 by y^2

2r^4y^4/r^8

Lastly divide r^4 by r^8

2y^4/r^4

Hence, the equivalent expression of 14r^4y^6/7r^8y^2 is 2y^4/r^4

Read more about equivalent expression at:

brainly.com/question/2972832

#SPJ1

3 0
2 years ago
Which expression is equivalent to sin(0.6x) − sin(0.4y)?
enyata [817]
1.5 is the answer for the question <span />
4 0
4 years ago
Read 2 more answers
A town of 8000 grows 3% yearly how long will it take to reach 16300
Tems11 [23]

Answer:

around 67 years

Step-by-step explanation:

hope this helps :)

8 0
3 years ago
Read 2 more answers
Find the solution to the differential equation<br><br> dB/dt+4B=20<br><br> with B(1)=30
natita [175]

Answer:

The solution of the differential equation is B=5+25e^{-4t+4}

Step-by-step explanation:

The differential equation \frac{dB}{dt}+4B=20 is a first order separable ordinary differential equation (ODE). We know this because a separable first-order ODE has the form:

y'(t)=g(t)\cdot h(y)

where <em>g(t)</em> and <em>h(y) </em>are given functions<em>. </em>

We can rewrite our differential equation in the form of a first-order separable ODE in this way:

\frac{dB}{dt}+4B=20\\\frac{dB}{dt}=20-4B\\\frac{dB}{dt}=4(5-B)\\\frac{1}{5-B}\frac{dB}{dt}=4

Integrating both sides

\frac{1}{5-B}\frac{dB}{dt}=4\\\frac{1}{5-B}\cdot dB=4\cdot dt\\\\\int\limits {\frac{1}{5-B}} \, dB=\int\limits {4} \, dt

The integral of left-side is:

\int\limits {\frac{1}{5-B}} \, dB\\\mathrm{Apply\:u-substitution:}\:u=5-B\\\int\limits {\frac{1}{5-B}} \, dB=\int\limits {\frac{1}{u}} \, dB\\\mathrm{du=-dB}\\-\int\limits {\frac{1}{u}} \,du\\\mathrm{Use\:the\:common\:integral}:\quad \int \frac{1}{u}du=\ln \left(\left|u\right|\right)\\-\int\limits {\frac{1}{u}} \,du =-\ln \left|u\right|\\\mathrm{Substitute\:back}\:u=5-B\\-\ln \left|5-B\right|\\\mathrm{Add\:a\:constant\:to\:the\:solution}\\-\ln \left|5-B\right|+C

The integral of right-side is:

\int\limits {4} \, dt = 4t + C

We can join the constants, and this is the implicit general solution

-\ln \left|5-B\right|+C=4t + C\\-\ln \left|5-B\right|=4t + D

If we want to find the explicit general solution of the differential equation

We isolate B

-\ln \left|5-B\right|=4t + D\\\ln \left|5-B\right|=-4t+D\\\left|5-B\right|=e^{-4t+D}

Recall the definition of |x|

|x|=\left \{ {{x, \:if \>x\geq \>0 } \atop {-x, \:if \>x0}} \right.

So

\left|5-B\right|=e^{-4t+D}\\5-B= \pm \:e^{-4t+D}\\B=5 \pm \:e^{-4t+D}\\B=5\pm \:e^{-4t}\cdot e^{D}\\B=5+Ae^{-4t}

where A=\pm e^{D}

Now B(1) =30 implies

B=5+Ae^{-4t}\\30=5+Ae^{-4}\\30-5=Ae^{-4}\\25e^{4}=A

And the solution is

B=5+(25e^{4})e^{-4t}\\B=5+25e^{-4t+4}

8 0
4 years ago
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