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ipn [44]
2 years ago
6

URGENT PLEASE HELP HELP HELP ASAP!!! PLEASE HELP ME

Mathematics
1 answer:
tigry1 [53]2 years ago
4 0

Answer:

ei nu înțeleg limba sory

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PLS HELP WITH THISS!!! I WILL GIVE BRAINLIEST
kozerog [31]

Answer:

D&B

Step-by-step explanation:

turn 6 to a fraction which is 6/1

So you keep the first fraction the same

change the division sign to a multiplication sign

change 3/4 to 4/3

so 6/1x4/3

multiply straight across the top and bottom

you get 24/3

simplified is 1/8lbs

5 0
3 years ago
If the probability of a student taking a calculus class is 0.10, the probability of taking a statistics class is 0.90, and the p
Stells [14]

Answer:

93% probability of a student taking a calculus class or a statistics class

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student takes a calculus class.

B is the probability that a student takes a statistics class.

We have that:

A = a + (A \cap B)

In which a is the probability that a student takes calculus but not statistics and A \cap B is the probability that a student takes both these classes.

By the same logic, we have that:

B = b + (A \cap B)

The probability of taking a calculus class and a statistics class is 0.07

This means that A \cap B = 0.07

The probability of taking a statistics class is 0.90

This means that B = 0.9. So

B = b + (A \cap B)

0.9 = b + 0.07

b = 0.83

The probability of a student taking a calculus class is 0.10

This means that A = 0.1

A = a + (A \cap B)

0.1 = a + 0.07

a = 0.03

What is the probability of a student taking a calculus class or a statistics class

A \cup B = a + b + A \cap B = 0.03 + 0.83 + 0.07 = 0.93

93% probability of a student taking a calculus class or a statistics class

5 0
3 years ago
ERRE
Karo-lina-s [1.5K]

y-5

2y+ 1

y-5

6y+7

y-5

2y+5

y-5

6y+ 7

-2y-10

2y+5

-2y-10

3 0
3 years ago
Thickness measurements of ancient prehistoric Native American pot shards discovered in a Hopi village are approximately normally
storchak [24]

Answer:

a) 0.1587

b) 0.0475

c) 0.7938

Step-by-step explanation:

Let's start defining our random variable.

X : ''Thickness (in mm) of ancient prehistoric Native American pot shards discovered in a Hopi village''

X is modeled as a normal random variable.

X ~ N(μ,σ)

Where μ is the mean and σ is the standard deviation.

To calculate all the probabilities, we are going to normalize the random variable X.

We are going to call to the standard normal distribution ''Z''.

[(X - μ) / σ] ≅ Z

We normalize by subtracting the mean to X and then dividing by standard deviation.

We can find the values of probabilities for Z in a standard normal distribution table.

We are going to call Φ(A) to the normal standard cumulative distribution evaluated in a value ''A''

a)

P(X

P(ZΦ(-1) = 0.1587

b)

P(X>7)=P(\frac{X-4.5}{1.5}>\frac{7-4.5}{1.5})

P(Z>1.666)=1-P(Z\leq 1.666)=

1 - Φ(1.666) = 1 - 0.9525 = 0.0475

c)

P(3

P(-1 Φ(1.666) - Φ(-1) = 0.9525 - 0.1587 = 0.7938

8 0
3 years ago
Find the solutions to the equation below x^2-25=0
Arlecino [84]

Answer:

x=5,x=-5

Step-by-step explanation:

The screenshot below will explain the answer

3 0
3 years ago
Read 2 more answers
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