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antoniya [11.8K]
3 years ago
15

HELPPP quick math question

Mathematics
1 answer:
emmasim [6.3K]3 years ago
4 0

e^{-.15x}=.42

ln e^{-.15x}= ln (.42)

-.15x = ln(.42)

x = ln(.42)/-.15

x=5.78333718

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The width of a rectangle is 5 meters less than its​ length, and the perimeter is 34 meters. Find the length and width of the rec
Alona [7]

Answer:

Length = 11

Width = 6

Step-by-step explanation:

We know that the length is x and the width is x - 5 since it is 5 less than the length.

The equation to find the perimeter of a rectangle is 2w + 2l

We will plug in the values and solve

2(x-5) + 2(x) = 34

2x - 10 + 2x = 34

4x - 10 = 34

4x = 44

x = 11

Since the length is simply x, we know that it is 11. We subtract 5 to find the width.

11 - 5 = 6.

The width is 6.

3 0
3 years ago
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Answer:

hi

Step-by-step explanation:

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3 years ago
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(0.2c^3)^2–0.01c^4(4c^2–100)
Debora [2.8K]
The answer should be C^4
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Classify each sequence as arithmetic, geometric or neither
Karolina [17]

Answer:

Geometric sequence = ⁵/9, ⁵/3, 5, 15, 45. . .

Arithmetic sequence = 16, 11, 6, 1, -4 . . .

Step-by-step explanation:

A geometric sequence is a sequence of numbers, in which every number in the sequence after the first term is multiplied by a common ratio, which gives us the next term. The common ratio is the ratio of a term to the term before it.

On the other hand, an arithmetic sequence is a sequence of number have a common difference between each consecutive terms. This common difference is gotten by subtracting a term from the term before it.

Now let's examine each sequence given:

==>16, 11, 6, 1, -4 . . .

11 - 16 = -5

6 - 11 = -5

1 - 6 = -5

-4 - 1 = -5

This is an arithmetic sequence. The commons difference "-5" is the same

==>⁵/9, ⁵/3, 5, 15, 45. . .

⁵/3 ÷ ⁵/9 = ⁵/3 × ⁹/5 = ⁹/3 = 3

5 ÷ ⁵/3 = ⁵ × ⅗ = 3

15 ÷ 5 = 3

45 ÷ 15 = 3

The common ratio "3" is the same. This is a geometric sequence.

3 0
3 years ago
TO ANYONE WHO WILL HELP ME..
NikAS [45]

Answer:

there isn't a math question

Step-by-step explanation:

4 0
3 years ago
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