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Fittoniya [83]
3 years ago
8

This is pretty confusing please help!!!!!

Mathematics
1 answer:
rusak2 [61]3 years ago
7 0
True it’s true hope this helps
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Find all the points, if any, where the graph of 12x-5y=0 intersects (x+12)^2+(y-5)^2=169.
WITCHER [35]
I: 12x-5y=0
II:(x+12)^2+(y-5)^2=169

with I:
12x=5y
x=(5/12)y
-> substitute x in II:
((5/12)y+12)^2+(y-5)^2=169
(25/144)y^2+10y+144+y^2-10y+25=169
(25/144)y^2+y^2+10y-10y+144+25=169
(25/144)y^2+y^2+144+25=169
(25/144)y^2+y^2+169=169
(25/144)y^2+y^2=0
y^2=0
y=0

insert into I:
12x=0
x=0

-> only intersection is at (0,0) = option B
6 0
3 years ago
Read 2 more answers
Due to manufacturing error, three cans of regular soda were accidentally filled with diet soda and placed into a 24 pk. Suppose
Goryan [66]

Hope this helps you If you need any more help let me know in the comments

6 0
3 years ago
.
Anuta_ua [19.1K]
Lets say you have 5 apples, but the you give away 3 of them.
To work how many you have left you take away.
5-3 = 2

Lets apply this with fractions now.
You have 9/7 yard, but then you give away 7/20 yard.
Now you take them away:
9/7 minus 7/20 = 131/140

Hope this helps :)
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8 0
3 years ago
The quarterback of a football team releases a pass at a height of 6 feet above the playing field, and the football is caught by
motikmotik

Answer:

t = 25.1seconds

Step-by-step explanation:

X(t)= 16cos75°t

Y(t)= 6 + (Vosin75°t - 16t^2)

Converting 78 yards to feet :

1 yard = 3 feet

78feet =?

78×3=234 feet

Y(t)= number of feet above the ground at t seconds

VoCos75° t = 234

t = 234/(VoCos75°)

At this time,4 = y(234/VoCos75°)

4 = 6 + VoSin75°(234/VoCos75) - 16(234/VoCos75°)^2

Vo= 140.66ft/s

Time,t= 234/(140.66× Cos75°)

t = 25.087seconds

t= 25.1 seconds (1 decimal place)

8 0
3 years ago
(84x - 69y) - (65x + 34y)
Svetach [21]

(84x - 69y) - (65x + 34y)

Remove the parenthesis and combine the like terms:

84x - 65x = 19x

-69y - 34y = -103y

Combine for final answer:

19x -103y

6 0
4 years ago
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